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Kitty [74]
3 years ago
9

Could anyone help me with these two questions? I need the answer by November 4th

Mathematics
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

Answer for question 2: A

Answer for question 3: -0.728

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The length of a rectangular deck is 4 times it’s width. If the deck’s perimeter is 30ft, what is the deck’s area?
ioda

Try this solution (note, this is not the shortest way):

1. if the given length is 'l' and the width is 'w', then according to the condition 4*l=w;

2. according to the condition the perimeter is 30 ft. Formula of the perimeter is P=2(l+w), then 2(l+w)=30;

3. if to substitute '4*l' instead of 'w', the formula of the perimeter (from item no. 2) will be as 2(4*l+l)=30 or 10*l=30 ⇒ l=3 ft. The length is 3 ft.!

4. if l=3 ft., then w=4*3=12 ft. The width is 12 ft.!

5. Area is

A=w*l; A=12*3=<u>36 ft²</u>

7 0
3 years ago
Answer please I need the help lol so as soon as possible will be great! Thanks!
Vikentia [17]

Answer:

pretty sure it's irrational numbers

6 0
3 years ago
Read 2 more answers
List the independent and dependent variable in the given relationship.
kaheart [24]
The independent variable is your input (x-value) and the dependent variable (y-value) depends on what the input is.

y = 10x

y is total money earned
x = number of lawns mowed

The first answer listed
4 0
3 years ago
Read 2 more answers
Solve:<br><br><img src="https://tex.z-dn.net/?f=%5Cunderset%7Bx%5Crightarrow~3%7D%7B%5Clim%7D~%5Cdfrac%7B2x%5E2-18%7D%7Bx%5E2-3x
vodomira [7]

Hello, please consider the following.

\displaystyle \lim_{x\rightarrow3}~\dfrac{2x^2-18}{x^2-3x} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x^2-3^2)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x-3)(x+3)}{x(x-3)} \\ \\ \\ =\lim_{x\rightarrow3}~\dfrac{2(x+3)}{x} \\ \\ \\=\dfrac{2(3+3)}{3}\\ \\ \\=\dfrac{2*3*2}{3} =\Large \boxed{\sf \bf \ 4 \ }

Thank you

8 0
3 years ago
Anthony has 115 book in his room .He is storing them in boxes .Each box holds 17 book .How many boxes does Anthony need?
ElenaW [278]
He will need 7 boxes
7 0
3 years ago
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