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Kitty [74]
3 years ago
9

Could anyone help me with these two questions? I need the answer by November 4th

Mathematics
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

Answer for question 2: A

Answer for question 3: -0.728

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PLEASE HELP ASAP!!!!!!
Masja [62]
The answer is that they will meet at 7.20 pm ! hope this helped
8 0
3 years ago
6x^2-5x-4=0 <br> solving quadratics by factoring (answer with {} around it)
stepan [7]

Step-by-step explanation:

6x²–5x–4 = 0

6×4 = 24..

write many ways 24 can be written..

24 = (6×4), (1×24), (12×2), (8×3)

(8×3) --> –8+3 = –5

6x²+3x–8x–4 = 0

6x(x+½)–8(x+½) = 0

(6x–8)(x+½) = 0

6x–8 = 0, x+½ = 0

6x = 8, x = –½

x = 4/3, –½

3 0
3 years ago
Please help me answer this :)! <br> I will give braisnlt
djyliett [7]

Answer: I don't see anything

Step-by-step explanation:

3 0
3 years ago
What is the vertical asymptote for this function?<br> y=1/x-2
nataly862011 [7]

Answer: x = 0

Step-by-step explanation: so x = 0 is the equation of the vertical asymptote, and 0 must be left out of the domain: (−∞,0)U(0,∞) in interval notation.

8 0
3 years ago
19. Find the current in a circuit if the power is 500 W (watts) and the resistance is 25 ohms. Round off your answer to two deci
HACTEHA [7]

Answer:

A

Step-by-step explanation:

The formula that relates current, power and resistance is

I=\sqrt{\frac{P}{R}}

Where

I is the current (in amperes)

P is the power (in watts)

R is the resistance (in ohms)

We know P = 500 and R = 25, we plug them into the formula and solve for I:

I=\sqrt{\frac{P}{R}}\\I=\sqrt{\frac{500}{25}}\\I=\sqrt{20}\\ I=4.47

Correct answer is 4.47 Amperes, or choice A.

4 0
3 years ago
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