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enot [183]
3 years ago
15

Resuelve:

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
4 0

Answer:

A partir del problemas vamos a crear una ecuación donde X es una docena de huevos y Y una libra de mantequilla

entonces: 4 docenas de huevos y 3 libras de mantequilla es igual a 14.100

en mi primera ecuación seria: 4X + 3Y = 14.100

ahora haremos la segunda ecuacion: tres docenas y 1 libra de mantequilla

en mi segunda ecuación seria: 3X + 1Y = 8.700 el plan es sumar las dos ecuaciones pero yo quiero que al sumarlas la variable "Y" desaparezca así que mi segunda ecuación la voy a multiplicar pór (-3) quedándome todo así:

primera ecuación: 4X + 3Y = 14.100

segunda ecuacion multiplicada por -3: -9X - 3Y = -26.1

al sumarlas obtengo como resultado: -5X = -12

resolviendo esa ecuacion obtengo que X=  

X=2.4

luego reemplazas X en la primera ecuación: 4X + 3Y = 14.100

reemplazando seria: 4 x (2.4) + 3Y =14.100

9.6 + 3Y = 14.1000

3Y= 14.100 - 9.6

Y=  

Y=1.5

entonces concluimos que la docena de huevos cuesta 2.4 $ y la libra de mantequilla 1.5 $

Step-by-step explanation:

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\begin{gathered} x-4=4-4 \\ x-4=0 \end{gathered}

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\begin{gathered} (x-1+i)(x-1-i)= \\ x^2-x-ix-x+1+i+ix-i-(i^2)= \\ x^2-2x+1-(-1)= \\ x^2-2x+1+1= \\ x^2-2x+2 \end{gathered}

Multiply it by (x - 4)

\begin{gathered} f(x)=(x-4)(x^2-2x+2) \\ f(x)=x^3-2x^2+2x-4x^2+8x-8 \\ f(x)=x^3-6x^2+10x-8 \end{gathered}

The answer is

f(x)=x^3-6x^2+10x-8

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