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3 years ago

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1 answer:

5 0

Yes, large muscles occur in some other living things. I think this because lets say you have a cheetah. Well, that cheetah runs very fast AND uses muscular endurances to hunt and chase its prey down. So yes, they start to devolp some large muscles. Some other living things that might have large muscles could be a bear, rhino, lion, tiger, or even a dog. As you can see, its more so the larger animals that devolp these large muscles.

Explanation:

None of this is copyed and pasted.

Sorry if it took to long.

Have a great day and good luck friend!

Brainliest is appreciated.

- Lea

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4 years ago

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3 years ago

The order of the genes on a plant chromosome is A, B, C, where A and B are located 10 cM apart and B and C are located 3 cM apar

Nonamiya [84]

Answer:

Double Crossing-over prob = 0.3%
Simple Crossing-Over prob A-B = 9.7%
Simple Crossing-Over prob B-C = 2.7%
Total Crossing-Over prob = 12.7%

Explanation:

<u>Available data</u>:

order of the genes on a plant chromosome is A, B, C
A and B are located 10 cM apart
B and C are located 3 cM apart

The genetic distance = recombination frequency x 100 expressed in map units (MU). One centiMorgan (cM) equals one map unit (MU).

We can use the provided map with the distances between genes to predict the occurrence of any kind of recombinant gamete.

We know that there is a probability of a simple crossing over to occur between genes A and B, or between genes B and C. And we also know that there is a probability of double crossing-over occurrence.

We can get the probability of the double-crossing over by multiplying the recombination frequencies between A-B and B-C. So,

DCO prob = recombination frequency A-B x recombination frequency B-C

= 0.1 x 0.03 = 0.003 = 0.3%

DCO prob = 0.3%

According to this, we would expect to find

0.15% AbC
0.15% aBc

Now we need to know what are the probabilities of getting a simple crossing-over, SCO. We already have the genetic distances between genes. 10 cM equals 0.1 of recombination frequency, and 3cM equals 0.03 of recombination frequency. However, we can not estimate the probabilities of simple crossing over using only this information, because this data is including the probabilities of the double crossing-over occurrence. So we need to substrate this percentage.

SCO prob A-B = 0.1 - 0.003 = 0.097 = 9.7%

SCO prob A-B = 9.7%

we would expect to find

4.85% Abc
4.85% aBC

SCO prob B-C = 0.03 - 0.003 = 0.027 = 2.7%

SCO prob B-C = 2.7%

we would expect to find

1.35% ABc
1.35% abC

The total Crossing-over probability, TCO, is then the sum of all the crossing over probabilities,

TCO= SCO A-B + SCO B-C + DCO

TCO prob = 9.7% + 2.7% + 0.3%

TCO = 12.7%

8 0

3 years ago