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3 years ago

How do I find the value of Q in the following systems so my solution to the system is

1 answer:

4 0

Hello,

if the solution is infinite : the line x-3y=4 ,
so there is one line and not 2

==>x-3y=4 multiplied by 2
2x-6y=8=Q

Q=8

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If a $200 billion increase in investment spending creates $200 billion of new income in the first round of the multiplier proces

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3 years ago

Factors of 9 simple question

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2 years ago

A cylinder has a height of 16 cm and a radius of 5 cm. A cone has a height of 12 cm and a radius of 4 cm. If the cone is placed

AlexFokin [52]

Given:
Cylinder: height = 16 cm ; radius = 5 cm
cone: height = 12 cm ; radius = 4 cm

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4 0

2 years ago

Read 2 more answers

Can anybody help me please

GREYUIT [131]

Question 7: Option 1: x = 33.5°

Question 8: Option 3: x = 14.0°

Step-by-step explanation:

Question 7:

In the given figure, the value of perpendicular and hypotenuse is given, so we have to use any trigonometric ratio to find the value of angle as the given triangle is a right-angled triangle

So,

Perpendicular = P = 32

Hypotenuse = H = 58

So,

$sin\ x = \frac{P}{H}\\sin\ x = \frac{32}{58}\\sin\ x = 0.5517\\x = sin^{-1} ( 0.5517)\\x =33.48$

Rounding off to nearest tenth

x = 33.5°

Question 8:

In the given figure, the value of Base and Perpendicular is given, we will use tangent trigonometric ratio to find the value of x

So,

Perpendicular = P = 5

Base = B = 20

So,

$tan\ x = \frac{P}{B}\\tan\ x = \frac{5}{20}\\tan\ x = 0.25\\x = tan^{-1} (0.25)\\x = 14.036$

Rounding off to nearest tenth

x = 14.0°

Keywords: Right-angled triangle, trigonometric ratios

Learn more about trigonometric ratios at:

#LearnwithBrainly

8 0

3 years ago

F(x) = 3x + 6 please help quickly!!!!!!!

Georgia [21]

Given the function, f(x) = 3x + 6, we can solve for f(a), f(a + h) and $\frac{(f(a + h) - f(a)) }{h}$ by substituting their values into f(x) = 3x + 6. We will have the following:

$\mathbf{f(a) = 3a + 6}\\\\\mathbf{f(a + h) = 3a + 3h + 6}\\\\\mathbf{\frac{(f(a + h) - f(a)) }{h} = 6}$

Given:

f(x) = 3x + 6

We are told to find:

f(a)
f(a + h), and
$\frac{(f(a + h) - f(a)) }{h}$

1. Find f(a):

Substitute x = a into f(x) = 3x + 6

f(a) = 3(a) + 6

f(a) = 3a + 6

2. Find f(a + h):

Substitute x = a + h into f(x) = 3x + 6

f(a + h) = 3(a + h) + 6

f(a + h) = 3a + 3h + 6

3. Find $\frac{(f(a + h) - f(a)) }{h}$ :

Plug in the values of f(a + h) and f(a) into $\frac{(f(a + h) - f(a)) }{h}$

Thus:

$\frac{((3a + 3h + 6) - (3a + 6)) }{h}\\\\\frac{(3a + 3h + 6 - 3a - 6) }{h}\\\\$

Add like terms

$\frac{(3a - 3a + 3h + 6 - 6) }{h}\\\\= \frac{3h }{h}\\\\\mathbf{= 3}$

Therefore, given the function, f(x) = 3x + 6, we can solve for f(a), f(a + h) and $\frac{(f(a + h) - f(a)) }{h}$ by substituting their values into f(x) = 3x + 6. We will have the following:

$\mathbf{f(a) = 3a + 6}\\\\\mathbf{f(a + h) = 3a + 3h + 6}\\\\\mathbf{\frac{(f(a + h) - f(a)) }{h} = 6}$

Learn more here:

brainly.com/question/8161429

6 0

2 years ago