Answer:
57
Step-by-step explanation:
7-3=4
3x4=12/3=4
do that two times because there is two triangles
7x7=49
4+4+49=57
Answer:
2
Step-by-step explanation:
-3 log₂ (-n + 10) = -16+7
-3 log₂ (-n + 10) = -9
log₂ (-n + 10) = -9/-3
log₂ (-n + 10) = 3
-n + 10 = 2^3
-n + 10 = 8
n=2
Answer:
2(3x + 7)(2x - 1)
Step-by-step explanation:
You can see it a little easier if you take out a common factor of 2
2(6x^2 + 11x - 7)
The 6 leaves you with a lot of factors, the 7 does not. It only has 2 factors.
Let 6 factor into 2 and 3 and the 7 into 7 and 1
2(3x - 1 )(2x + 7)
Now remove the brackets.
2(6x^2 + 21x - 2x - 7) This obviously does not work but we'll combine like terms anyway.
2(6x^2 + 19x - 7)
So we'll try it again
2(3x + 7)(2x - 1)
2(6x^2 + 14x - 3x - 7) Looks like we have it.
2(6x^2 + 11x - 7)
So the right factors are
2(3x + 7)(2x - 1)
Answer:
Step-by-step explanation:
Well believe it or not, that is not a simple question. Just look at what you left us to define. Your talking (for example) about a square and wondering what the vertex of B is called (other than a vertex.)
I think vertex is the only thing you can call B. But then there's a problem. What do you call the points on a segment? ___________? There are endpoints, but what's between those endpoints? I think you would just give them letter names and call them points. A point is dimensionless and there an infinite number of them in a segment.
Phew!!!
The correct question is
Which is the best approximation to a solution of the equation
e^(2x) = 2e^{x) + 3?
we have that
e^(2x) = 2e^{x) + 3-----------> e^(2x)- 2e^{x) - 3=0
the term
e^(2x)- 2e^{x)----------> (e^x)²-2e^(x)*(1)+1²-1²------> (e^x-1)²-1
then
e^(2x)- 2e^{x) - 3=0--------> (e^x-1)²-1-3=0------> (e^x-1)²=4
(e^x-1)=2--------> e^x=3
x*ln(e)=ln(3)---------> x=ln(3)
ln(3)=1.10
hence
x=1.10
the answer is x=1.10
