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3 years ago

ANSWER 22 PLEASE...

Mathematics

1 answer:

julia-pushkina [17]3 years ago

5 0

A. Is a congruent triangle

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Question 12

Anestetic [448]

40 kilometers I think

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3 years ago

There are 7 school buses taking students on a field trip. There are 37 students on each bus. How many students are going on the

vovangra [49]

Answer:

259 Students

Step-by-step explanation:

So, since there are 37 children in each bus, and 7 busses, we need to multiply the two together.

$37\times7 = 259$

8 0

3 years ago

)) In a right triangle, a and b are the lengths of the legs and c is the length of the

kondor19780726 [428]

Answer:

5.66 inches

Step-by-step explanation:

${a}^{2} + {b }^{2} = {c}^{2}$

a² + 7² = 9²

a² + 49 = 81

a² + 49 - 49 = 81 - 49

a² = 32

a = square root of 32

a = 5.6568 or 5.66 inches

I used the Pythagorean Theorem to solve this.

7 0

3 years ago

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(b) dy/dx = (x - y+ 1)^2

Elanso [62]

Substitute $v(x)=x-y(x)+1$ , so that

$\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}$

Then the resulting ODE in $v(x)$ is separable, with

$1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx$

On the left, we can split into partial fractions:

$\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx$

Integrating both sides gives

$\dfrac{\ln|1-v|+\ln|1+v|}2=x+C$

$\dfrac12\ln|1-v^2|=x+C$

$1-v^2=e^{2x+C}$

$v=\pm\sqrt{1-Ce^{2x}}$

Now solve for $y(x)$ :

$x-y+1=\pm\sqrt{1-Ce^{2x}}$

$\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}$

3 0

3 years ago

Is the relation represented in this table a function?

Inessa05 [86]

Answer:

i think so?

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers