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Hatshy [7]
3 years ago
15

ANSWER 22 PLEASE...

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
A. Is a congruent triangle
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Anestetic [448]
40 kilometers I think
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3 years ago
There are 7 school buses taking students on a field trip. There are 37 students on each bus. How many students are going on the
vovangra [49]

Answer:

259 Students

Step-by-step explanation:

So, since there are 37 children in each bus, and 7 busses, we need to multiply the two together.


37\times7 = 259

8 0
3 years ago
)) In a right triangle, a and b are the lengths of the legs and c is the length of the
kondor19780726 [428]

Answer:

5.66 inches

Step-by-step explanation:

{a}^{2}  +  {b }^{2}   =   {c}^{2}

a² + 7² = 9²

a² + 49 = 81

a² + 49 - 49 = 81 - 49

a² = 32

a = square root of 32

a = 5.6568 or 5.66 inches

I used the Pythagorean Theorem to solve this.

7 0
3 years ago
Read 2 more answers
(b) dy/dx = (x - y+ 1)^2
Elanso [62]

Substitute v(x)=x-y(x)+1, so that

\dfrac{\mathrm dv}{\mathrm dx}=1-\dfrac{\mathrm dy}{\mathrm dx}

Then the resulting ODE in v(x) is separable, with

1-\dfrac{\mathrm dv}{\mathrm dx}=v^2\implies\dfrac{\mathrm dv}{1-v^2}=\mathrm dx

On the left, we can split into partial fractions:

\dfrac12\left(\dfrac1{1-v}+\dfrac1{1+v}\right)\mathrm dv=\mathrm dx

Integrating both sides gives

\dfrac{\ln|1-v|+\ln|1+v|}2=x+C

\dfrac12\ln|1-v^2|=x+C

1-v^2=e^{2x+C}

v=\pm\sqrt{1-Ce^{2x}}

Now solve for y(x):

x-y+1=\pm\sqrt{1-Ce^{2x}}

\boxed{y=x+1\pm\sqrt{1-Ce^{2x}}}

3 0
3 years ago
Is the relation represented in this table a function?
Inessa05 [86]

Answer:

i think so?

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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