At 4:00 A.M., the outside temperature was –28°F. By 4:00 P.M. that same day, it rose 38 degrees. What was the temperature at 4:0
2 answers:
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Answer:
x = 2
Step-by-step explanation:
For quadratic ax^2 +bx +c, the axis of symmetry is x = -b/(2a).
Here, we have a=2, b=-8, so the axis of symmetry is ...
x = -b/(2a) = -(-8)/(2(2)) = 8/4
x = 2
