At 4:00 A.M., the outside temperature was –28°F. By 4:00 P.M. that same day, it rose 38 degrees. What was the temperature at 4:0
2 answers:
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Hope this helps. Solution is attached on the image above.
Answer:133.33%
Step-by-step explanation:
For given change in fractions from to
The initial fraction=
New fraction=
Change in fractions= New fraction-Initial fraction
As change in fraction is positive thus it is an increase.