At 4:00 A.M., the outside temperature was –28°F. By 4:00 P.M. that same day, it rose 38 degrees. What was the temperature at 4:0
2 answers:
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Answer:
b=0.00906m
Step-by-step explanation:
Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation
where
A=area=32.5m^2
h=altitude=7172m
b=base
Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality
solving