This answer did not come from me but credit to ApusApus
We have been given that adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall.
We need to find the area of normal curve above the raw score 79.
First of all let us find the z-score corresponding to our given raw score.
, where,
,
,
,
.
Upon substituting our given values in z-score formula we will get,
Now we will find the P(z>3) using formula:
Using normal distribution table we will get,
Let us convert our answer into percentage by multiplying 0.00135 by 100.
Therefore, approximately 0.135% of the adult male population is taller than the average basketball player and option A is the correct choice.
Answer:
23.49
Step-by-step explanation:
107.04-83.55= 23.49
Answer:The short answer would be y=2x+4
Step-by-step explanation:
Here's why standard form is y=mx+b.
Thus, if we solved 2x-y=-4, we would get y+2x+4.
1. 2x-y=-4
2. -y= -2x-4
3. y=2x+4
1.
x y
0 0
1 2
2 4
3 6
2. y = 2x+0 (or just y = 2x )
3. The slope is 2
Hope this helped!
Th volume that reflects these changes will be: 3/21 (L*W*H), hope that helps.