Answer:
2 3/4
Step-by-step explanation:
6 19/20 - 4 1/5 = ?
6 19/20 - 4 4/20 = ?
2 15/20 = ?
Simplified = 2 3/4
Answer:
It's position at time t = 5 is 593.
Step-by-step explanation:
The velocity v(t) is the integral of the acceleration a(t)
The position s(t) is the integral of the velocity v(t)
We have that:
The acceleration is:

Velocity:

K is the initial velocity, that is v(0). Since V(0) = 13, K = 13
Then

Position:

Since s(0) = 3

What is its position at time t=5?
This is s(5).



It's position at time t = 5 is 593.
Answer is =-1
implifying
-2x + 3 = -3x + 2
Reorder the terms:
3 + -2x = -3x + 2
Reorder the terms:
3 + -2x = 2 + -3x
Solving
3 + -2x = 2 + -3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3x' to each side of the equation.
3 + -2x + 3x = 2 + -3x + 3x
Combine like terms: -2x + 3x = 1x
3 + 1x = 2 + -3x + 3x
Combine like terms: -3x + 3x = 0
3 + 1x = 2 + 0
3 + 1x = 2
Add '-3' to each side of the equation.
3 + -3 + 1x = 2 + -3
Combine like terms: 3 + -3 = 0
0 + 1x = 2 + -3
1x = 2 + -3
Combine like terms: 2 + -3 = -1
1x = -1
Divide each side by '1'.
x = -1
Simplifying
x = -1
Answer:
α² +β² = 3 4/9
Step-by-step explanation:
Assuming α and β are solutions to the equation, it can be factored as ...
(x -α)(x -β) = 0
Expanding this, we get ...
x² -(α +β)x +αβ = 0
Dividing the original equation by 3, we find ...
x² +(1/3)x -5/3 ≡ x² -(α+β)x +αβ ⇒ (α+β) = -1/3, αβ = -5/3
We know that the square (α+β)² can be expanded to ...
(α +β)² = α² +β² +2αβ
α² +β² = (α +β)² -2αβ . . . . . . subtract 2αβ
Substituting the values for (α+β) and αβ, we find the desired expression is ...
α² +β² = (-1/3)² -2(-5/3) = 1/9 +10/3 = 31/9
α² +β² = 3 4/9
Answer:
3x^3+ 12x^2-15x
Step-by-step explanation:
First, you would have to distribute the 3x to everything in the parentheses. So you can write it out as (3x*x^2)+(3x*4x)+(3x*5). Solving this will give you the answer. We'll start off with (3x*x^2). Because we are MULTIPLYING, this part will equal to 3x^3. There is ONE x with 3x (think of it as 3x^1) and 2 x's in x^2, having a total of 3 x's, or x^3. Since the 3 is being multiplied as well, we can write it as 3x^3.
Second, we will solve (3x*4x). We are multiplying, so first we multiply 3*4 and then x*x. 3*4 is 12 and x*x is x^2. There are 2 x's being mutipled by each other, so the x becomes squared. Now we finish and multiply 12*x^2 wich is 12x^2.
Lastly, we solve (3x*5). 3x is being multiplied 5 times which gives us 15x.
I hope this helped :)