Answer:
30m
Step-by-step explanation:
<em>Since we are not told what to look for, we can find the maximum height reached by the rocket</em>
Given the rocket's flight approximately modeled by the equation
h(t) = - 12t ^ 2 + 36t + 3
At maximum height dh/dt = 0
dh/dt = --24t + 36
0 = -24t + 36
24t = 36
t= 36/24
t = 1.5s
Get the max height
h(1.5) = - 12 (1.5)^ 2 + 36(1.5) + 3
h(1.5) = - 12(2.25) + 54 + 3
h(1.5) = -27 + 57
h(1.5) = 30m
Hence the maximum height reached by the rocket is 30m
Answer:
Step-by-step explanation:
The relevant relations here are ...
- the sum of arc measures in a semicircle is 180°
- the sum of angles in a triangle is 180°
<h3>Arc measures</h3>
The given arc CD is part of the semicircular arc CDA. The remaining arc, DA, is the supplement of CD:
arc DA = 180° -CD = 180° -125° = 55°
Central angle AOD has the same measure, 55°. That is one of the acute angles in right triangle AOB, so the other one is the complement of 55°.
∠ABO = 90° -∠AOB = 90° -55°
∠ABO = 35°
<h3>Triangle angles</h3>
In right triangle ABC, angle ABC is given as 55°. The other acute angle, ACB, will be the complement of this.
∠ACB = 90° -∠ABC = 90° -55°
∠ACB = 35°
In the figure, angles ABO and ACB have measures of 35°.
Answer:x=-3 nonextraneous
Step-by-step explanation:
Answer:
<em>To solve system of equation by elimination, check if the values of x or y are lined up and have the same value.</em>
Or if the are not, take the numbers in x or y to multiply. Use the first to multiply the second equation and the second to multiply the first equation
<em>E</em><em>xample is, for the first step which is in italic form is</em>
<em> 2x + 3y =64...equation 1</em>
<em> 2x - 6y = 75...equation 2</em>
you can just eliminate for x by taking away equation 2 from equation 1
Or for step two which is in light form is
4x + 3y =64...equn 1
3x + 7y =80...equn2
to eliminate x, multiply equation 1 by 3 and equation 2 by 4
it will be 12x +12y =192
12x +28y =320
now you can solve.
Thanks
