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3 years ago

Rewrite the expression in the form a^n. 1/a^-5/6

Mathematics

2 answers:

Sav [38]3 years ago

7 0

Step-by-step explanation:

here's the answer to your question

sergejj [24]3 years ago

5 0

Answer:

$\frac{1}{a^{\frac{-5}{6} } }$

<u>OAmalOHopeO</u>

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What is -4x+3 as an ordered pair

Aleks [24]

Answer:x= {y-3} tell me if this is right thankyou!

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2 years ago

Pls help me with this

katrin [286]

Answer:

f(X)=2x is the correct answer

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3 years ago

What is the value of (–3 + 3i) + (–2 + 3i)?

Bess [88]

Answer:

6i - 5

Step by step:

Assuming x = i

Simplify step by step:

−3+3x−2+3x

=−3+3x+−2+3x

Combine Like Terms:

=−3+3x+−2+3x

=(3x+3x)+(−3+−2)

=6x+−5

5 0

4 years ago

Read 2 more answers

a triangle has vertices at (1, 1), (1, 2), and (3, 2). it is dilated by a scale factor of 3 within the origin as the center of d

PolarNik [594]

Answer:

(3,3), (3,6), (9,6)

Step-by-step explanation:

A triangle ABC has vertices at A(1, 1), B(1, 2), and C(3, 2).

The dilation by a scale factor of 3 within the origin as the center of dilation has the rule

$(x,y)\rightarrow (3x,3y)$

Hence,

$A(1,1)\rightarrow D(3,3)$
$B(1,2)\rightarrow E(3,6)$
$C(3,2)\rightarrow F(9,6)$

See attached diagram for details.

6 0

4 years ago

I really really really need help!!!!

Yakvenalex [24]

For $f$ to be continuous at $x=1$ , you need to have the limit from either side as $x\to1$ to be the same.

$\displaystyle\lim_{x\to1^-}f(x)=\lim_{x\to1^-}(|x-1|+2)=2$
$\displaystyle\lim_{x\to1^+}f(x)=\lim_{x\to1^+}(ax^2+bx)=a+b$

If $a=2$ and $b=3$ , then the limit from the right would be $2+3=5\neq2$ , so the answer to part (1) is no, the function would not be continuous under those conditions.

This basically answers part (2). For the function to be continuous, you need to satisfy the relation $a+b=2$ .

Part (c) is done similarly to part (1). This time, you need to limits from either side as $x\to2$ to match. You have

$\displaystyle\lim_{x\to2^-}f(x)=\lim_{x\to2^-}(ax^2+bx)=4a+2b$
$\displaystyle\lim_{x\to2^+}f(x)=\lim_{x\to2^+}(5x-10)=0$

So, $a$ and $b$ have to satisfy the relation $4a+2b=0$ , or $2a+b=0$ .

Part (4) is done by solving the system of equations above for $a$ and $b$ . I'll leave that to you, as well as part (5) since that's just drawing your findings.

8 0

3 years ago