$1.\:2^x=64, x=\boxed{6},\\2.\:x=\left(\frac{2}{3}\right)^3,x=\boxed{\frac{8}{125}}\\3.\:3\cdot (3^4)=3^x, x=\boxed{5}\\4.\:\frac{16}{25}=x^2,x=\boxed{\frac{4}{5}},$

Step-by-step explanation:

$1.\\\\2^x=64,\\\log 2^x=\log64,\\x\log 2=\log 64,\\x=\frac{\log 64}{\log 2}=\boxed{6}$

$2.\\x=\left(\frac{2}{5}\right)^3=\frac{2^3}{5^3}=\boxed{\frac{8}{125}}$

3. This problem incorporates an exponent property.

Exponent property used: $a^b\cdot a^c=a^{(b+c)}$ , yielding an answer of $\boxed{5}$

$4.\\\\\frac{16}{25}=x^2,\\x=\sqrt{\frac{16}{25}}=\frac{\sqrt{16}}{\sqrt{25}}=\boxed{\frac{4}{5}}$

3 0

3 years ago

Read 2 more answers

What’s the answer I don’t understand

Scorpion4ik [409]

Your answer is D. All of these statements are true.

5 0

3 years ago

Write each vector described below in component form and find its magnitude. Draw an arrow originating from (0,0) to

ElenaW [278]

Answer:

a = 3xi - 4yj b = -6xj c = -2xi + 2yj d = 5xi + 7yj

a ; b ; c ; d vectors

i and j unit vectors

Step-by-step explanation:

See attached file

8 0

3 years ago