Question

A triangle has sides with lengths of 3 feet, 6 feet, and 8 feet is it a right triangle?

Answer 1

Answer:

$Solution,\\Longest~side(h) = 8ft.\\Perpendicular(p) = 3ft.\\Base(b) = 6ft.\\Now, \\h^2 = (8)^2 = 64sq.ft.\\p^2+b^2 = 3^2+6^2 = 9+36 = 45sq.ft.\\Since, h^2\neq p^2+b^2, ~the~triangle~is~not~a~right~triangle.$