Answer:
6 squares to right and 6 squares down
Step-by-step explanation:
Go with the coordinate (-1, 5) on shape A
Hope it helps :)
Answer:
![\frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
Step-by-step explanation:
Ok, let's do this step by step....
![\sqrt[3]{\frac{10x^{5} }{54x^{8} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10x%5E%7B5%7D%20%7D%7B54x%5E%7B8%7D%20%7D%20%7D)
Let's first simplify the x's:
![\sqrt[3]{\frac{10}{54x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B54x%5E%7B3%7D%20%7D%20%7D)
Then we breakdown the 54 as 2 * 27 then simplify with the 10 above.
![\sqrt[3]{\frac{10}{2 * 27x^{3} } } = \sqrt[3]{\frac{5}{27x^{3} } }](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B10%7D%7B2%20%2A%2027x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B5%7D%7B27x%5E%7B3%7D%20%7D%20%7D)
Now, we can rewrite this as the following and solve the bottom part:
![\frac{\sqrt[3]{5} }{\sqrt[3]{27x^{3} } } = \frac{\sqrt[3]{5} }{3 \sqrt[3]{x^{3} } } = \frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B%5Csqrt%5B3%5D%7B27x%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3%20%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%20%7D%20%7D%20%3D%20%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
The solution is
![\frac{\sqrt[3]{5} }{3x}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7B5%7D%20%7D%7B3x%7D)
Answer:
$20,086.35
Step-by-step explanation:
To calculate the maturity value by compound interest, we will use the formula

where,
A = Maturity amount
P = Principal amount = $10,000
r = rate of interest = 4.65% = 0.0465
n = number of compounding periods = 365
t = time in years = 15 years
Now substituting the values,

= 

= 10,000(2.008635)
= 20086.353758 ≈ $20,086.35
The final value of your investment would be $20,086.35.
Answer:
(0,1508)
Step-by-step explanation:
If X is years, and (x,y) is the format, and no years have passed for the first census, then 0 fills in for X and the number of people fills in for y.