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Rus_ich [418]
3 years ago
11

The equation k = 1.6d gives an approximate relationship between d miles and k kilometers. The distance between Boise, Idaho, and

Reno, Nevada, is 430 miles. Express the distance in kilometers.
A.
431.6 km


B.
268.8 km


C.
688 km
Mathematics
2 answers:
Burka [1]3 years ago
8 0

Answer:  C) 688 km

=================================================

Work Shown:

k = 1.6d

k = 1.6*430

k = 688

430 miles is roughly equivalent to 688 km.

More accurately, 430 miles = 692.01792 km, so this approximation isn't too far off.

Inga [223]3 years ago
5 0

Answer: the answer is C. 688 km

RESULT

The distance between Boise, Idaho and Reno, Nevada is 688 kilometers.

Step-by-step explanation:

The equation k = 1.6d gives an approximate relationship between d miles and k kilometers. Express each distance in kilometers. the 430 miles between Boise, Idaho, and Reno, Nevada

k = 1.6 d

Where k is in kilometers n d in miles

The distance between Boise, Idaho and Reno, Nevada is 430

Substituting d= 430 we get,

k = 1.6(430)

k = 688

RESULT

The distance between Boise, Idaho and Reno, Nevada is 688 kilometers.

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Step-by-step explanation:

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3 years ago
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Andreyy89

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Decrease<br> M720.00 by 25%
netineya [11]

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8 0
3 years ago
Q4.
goblinko [34]

The coding of the statistic is used to make it easier to work with the large sunshine data set

  • The mean of the sunshine is 3.05\overline 6
  • The standard deviation is approximately  <u>18.184</u>

<u />

Reason:

The given parameters are;

The sample size, n = 3.

∑x = 947

Sample corrected sum of squares, Sₓₓ = 33,065.37

The mean and standard deviation = Required

Solution:

Mean, \ \overline x = \dfrac{\sum x_i}{n}

The mean of the daily total sunshine is therefore;

Mean, \ \overline x = \dfrac{947}{30} \approx 31.5 \overline 6

s = \dfrac{x}{10 } - \dfrac{1}{10}

  • E(s) = \dfrac{Ex}{10 } - \dfrac{1}{10}

E(s) = \dfrac{31.5 \overline 6}{10 } - \dfrac{1}{10} = 3.05 \overline 6

  • The mean ≈ 3.05\overline 6

Alternatively

,The \ mean \  of \  the \  daily  \ total  \ sunshine,  \, s = \dfrac{31.5 \overline 6 - 1}{10 } = 3.05\overline 6

The mean of the daily total sunshine, \overline s ≈3.05\overline 6

  • Var(s) = Var \left(\dfrac{x}{10 } - \dfrac{1}{10} \right)

Var(s) = \left(\dfrac{1}{10}\right)^2 \times Var \left(x \right)

Therefore;

Var(s) = \left(\dfrac{1}{10}\right)^2 \times 33,065.37 = 330,6537

Therefore;

  • s = \sqrt{330.6537} \approx 18.184

The standard deviation, s_s ≈ <u>18.184</u>

Learn more about coding of statistic data here:

brainly.com/question/14837870

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2 years ago
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