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3 years ago

Help me this is due this period please please ill mark brainiest with a bunch of points.

Mathematics

2 answers:

Verdich [7]3 years ago

6 0

Answer:

(-4,1)

Step-by-step explanation:

The answer is just where the two lines intersect

I'm rather tired so double check me on this but I'm getting about (-4,1) and it's asking for an approximation so think (-4,1) is fine

almond37 [142]3 years ago

6 0

Answer:

It's around (-4. 5, 1.5). It's somewhere in that range.

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3(x+y)=y

andrew-mc [135]

3(x+y)=y

y is not equal to zero

*Solution

1. The given equation is 3(x+y) = y and we are tasked to find the ratio between x and y. Distributing 3 to the terms in the parenthesis,

3(x+y) = y

3x + 3y = y

Transposing 3y to the right side OR subtracting 3y from both the left-hand side and the right-hand side of the equation would give

3x = -2y

Dividing both sides of the equation by 3,

x = (-2/3)y

Dividing both sides of the equation by y,

x/y = -2/3

Therefore, the ratio x/y has a value of -2/3 provided that y is not equal to zero.

6 0

3 years ago

A shirt costs $5 less than a sweater. Together they cost<br> $25. How much does the sweater cost?

Aleksandr-060686 [28]

Answer:

Shirt: $7.5

Sweater: $17.5

Step-by-step explanation:

25/2=12.5

Shirt is 5 less than Sweater

12.5-5=7.5

Add 5 to sweater cost

12.5+5=17.5

Shirt=7.5 Sweater=17.5

17.5+7.5=25

6 0

3 years ago

ANSWER THIS ASAP DONT SEND A FILE AT ALL !! I NEED THE ANSWER TO QUESTION

jasenka [17]

Answer: just use phot math

Step-by-step explanation:

4 0

3 years ago

All lines are straight or a triangle has four sides.

sveta [45]

This is a disjunction, B, because it has 2 statements with an OR in the middle.

7 0

4 years ago

Read 2 more answers

Evaluate the surface integral. s x2 + y2 + z2 ds s is the part of the cylinder x2 + y2 = 4 that lies between the planes z = 0 an

Leya [2.2K]

Parameterize the lateral face $T_1$ of the cylinder by

$\mathbf r_1(u,v)=(x(u,v),y(u,v),z(u,v))=(2\cos u,2\sin u,v$

where $0\le u\le2\pi$ and $0\le v\le3$ , and parameterize the disks $T_2,T_3$ as

$\mathbf r_2(r,\theta)=(x(r,\theta),y(r,\theta),z(r,\theta))=(r\cos\theta,r\sin\theta,0)$
$\mathbf r_3(r,\theta)=(r\cos\theta,r\sin\theta,3)$

where $0\le r\le2$ and $0\le\theta\le2\pi$ .

The integral along the surface of the cylinder (with outward/positive orientation) is then

$\displaystyle\iint_S(x^2+y^2+z^2)\,\mathrm dS=\left\{\iint_{T_1}+\iint_{T_2}+\iint_{T_3}\right\}(x^2+y^2+z^2)\,\mathrm dS$
$=\displaystyle\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}((2\cos u)^2+(2\sin u)^2+v^2)\left\|{{\mathbf r}_1}_u\times{{\mathbf r}_2}_v\right\|\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+0^2)\left\|{{\mathbf r}_2}_r\times{{\mathbf r}_2}_\theta\right\|\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}((r\cos\theta)^2+(r\sin\theta)^2+3^2)\left\|{{\mathbf r}_3}_r\times{{\mathbf r}_3}_\theta\right\|\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle2\int_{u=0}^{u=2\pi}\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv\,\mathrm du+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r^3\,\mathrm d\theta\,\mathrm dr+\int_{r=0}^{r=2}\int_{\theta=0}^{\theta=2\pi}r(r^2+9)\,\mathrm d\theta\,\mathrm dr$
$=\displaystyle4\pi\int_{v=0}^{v=3}(v^2+4)\,\mathrm dv+2\pi\int_{r=0}^{r=2}r^3\,\mathrm dr+2\pi\int_{r=0}^{r=2}r(r^2+9)\,\mathrm dr$
$=136\pi$

7 0

4 years ago