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den301095 [7]
3 years ago
13

Please solve this:

Mathematics
1 answer:
Kobotan [32]3 years ago
7 0

Answer:

<u>y</u><u> </u><u>is</u><u> </u><u>5</u><u>.</u>

Step-by-step explanation:

{ \sf{{2}^{y - 3} \times {3}^{2y - 8 } = 36}} \\  \frac{ {2}^{y} }{ {2}^{3}}  \times  \frac{ {3}^{2y} }{ {3}^{8} }  = 36 \\  \\  {2}^{y} . {3}^{2y}  = 36 \times  {2}^{3}  \times  {3}^{8}

Introduce log base 10:

log_{10}( {2}^{y}  \times  {3}^{2y} )  =  log_{10}(36 \times  {2}^{3}  \times  {3}^{8} )  \\  log_{10}( {2}^{y} )  +  log_{10}( {3}^{2y} )  = 6.28 \\ y log_{10}(2)  + 2y log_{10}(3)  = 6.28 \\ 0.3y + 0.95y = 6.28 \\ 1.25y = 6.28 \\ y = 5

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Step-by-step explanation:

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A difference of squares is the difference of two squared terms.

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We can factorize the difference of squared terms like this:

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Lets prove it:

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