All categories

2 years ago

Square ABCD is shown below.

Mathematics

1 answer:

valentina_108 [34]2 years ago

6 0

Answer:

35 is the length of BE

Step-by-step explanation:

2(2x + 5) = 8x - 50

4x + 10 = 8x -50

10+50 = 8x-4x

60= 4x

15 = x

2x + 5 = length of BE equal to length of DE

2(15) +5 = BE

30 +5

35 is the length of BE

You might be interested in

AHHHhHhHhHHhhHHHhHH!!!!!!!!

erma4kov [3.2K]

Answer:

8x4x2=64+24=88 the answer is 88 yw :) pls give brainliest

Step-by-step explanation:

4 0

2 years ago

Evaluate the expression: –(31 + 2) + 72 – (–5)2.

Rudiy27

Answer:

Step-by-step explanation:

Order of operations rules require that we do any work inside parentheses first. Thus,

–(31 + 2) + 72 – (–5)^2

becomes:

-33 + 72 - 25, or

Important: Please use " ^ " to denote exponentiation; (-5)2 is incorrect, whereas (-5)^2 or (-5)² is correct.

4 0

2 years ago

A college is currently accepting students that are both in-state and out-of-state. They plan to accept three times as many in-st

ziro4ka [17]

Answer:

0 < x ≤ 100 and 0 < y ≤ 300

Step-by-step explanation:

THIS IS THE COMPLETE QUESTION BELOW;

college is currently accepting students that are both in-state and out-of-state. They plan to accept three times as many in-state students as out-of-state, and they only have space to accept 100 out-of-state students. Let x = the number of out-of-state students and y = the number in-state students. Write the constraints to represent the incoming students at the college.

0 < x ≤ 100 and 0 < y ≤ 300

x > 0 and y > 0

0 < x ≤ 100 and y > 300

0 < x and y < 100

SOLUTION

they only have space to accept 100 out-of-state students,which means that the Maximum number of out-of-state students that can be accepted is 100

Then x= 100(Maximum number of out-of-state students that can be accepted)

They plan to accept three times as many in-state students as out-of-state which means that

Y = 3x(Maximum number of in-state students)

Then we can deduced that the numbee out-of-state students that can be accepted can lyes between the range of 0 and 100 which means from interval 0 to 100

Which can be written as 0 < x ≤ 100

But we need to know the interval for the Maximum number of in-state students(Y), to do that we need to multiply the equation above by 3 since Y = 3x

0 < x ≤ 100

3× 0 = 0

3× X = X

3× 100= 300

Then 0 < 3x≤ 300

But we know that Y = 3x then substitute into last equation

We have

0 < y ≤ 300

ThenBthe constraints to represent the incoming students at the college is

0 < x ≤ 100 and 0 < y ≤ 300

8 0

2 years ago

<img src="https://tex.z-dn.net/?f=%5Csf%20HELP%21" id="TexFormula1" title="\sf HELP!" alt="\sf HELP!" align="absmiddle" class="l

ehidna [41]

Answer:

x=13

Step-by-step explanation:

Switch sides:

2x−9=17

Add 9 to both sides:

2x−9+9=17+9

Simplify

2x=26

Divide both sides by 2:

2x/2 =26/2

Simplify to get the result.

x=13

8 0

2 years ago

Kyla spends 60 Minutes of each day exercising. Let d be the number of days that Kyla exercises, and let m represent the total nu

stealth61 [152]

Answer: There is linear relationship between the number of days that Kyla exercise in the total minutes that she exercises.

The independent variable is 'd' and m is the dependent variable which depends on the number of days she exercise.

The linear equation for the situation is given by

$m=60d$

Step-by-step explanation:

Let d be the number of days that Kyla exercises, and let m represent the total numbers of minutes she exercise.

Kyla spends 60 Minutes of each day exercising which is constant .

Then the total numbers of minutes she exercise(m) in d days is given by

$m=60d$ which is the linear equation.

The relationship between the number of days that Kyla exercise in the total minutes that she exercises is linear, where d is the independent variable, and m is the dependent variable which depends on the number of days she exercise.

[ad d increases m increases by rate of 60 minutes per day]

The linear equation for the situation is given by

$m=60d$

7 0

3 years ago