All categories

3 years ago

A parallelogram with an area of 211.41 m2 has a base that measures 24.3m. Find it’s height

Mathematics

2 answers:

guajiro [1.7K]3 years ago

5 0

Answer:

5137

Step-by-step explanation:

pishuonlain [190]3 years ago

4 0

The height of the parallelogram is 8.7 cm.

Step-by-step explanation:

<em>Given,</em>

Area of the parallelogram = 211.41 sq m

Base (b) = 24.3 m

To find the height of the parallelogram.

Formula

Area of a parallelogram with height h and base b is = b×h

According to the problem,

b×h = 211.41

or, h = 211.41÷24.3

or, h = 8.7

So,

The height of the parallelogram is 8.7 cm.

You might be interested in

A manager wants to determine if an employee training program has increased her employees’ customer satisfaction ratings. She ran

lubasha [3.4K]

Answer:

Step-by-step explanation:

The answer should be A
I hope that's ok if I am wrong pls correct me

6 0

2 years ago

Write 94% as a fraction in simplest form

lana [24]

9.4/10 is the simplest form

8 0

3 years ago

Read 2 more answers

Well can somebody help me ‍♀️

Rasek [7]

Yes, the new coordinates would be:

R': (9,9)
P': (3,3)
Q': (9,3)

You would multiply all of the current coordinates by three (its scale factor of enlargement) to obtain these answers. Hope this helps!

5 0

3 years ago

Jace invested $67,000 in an account paying an interest rate of 5 5/8% compounded monthly. Joseph invested $67,000 in an account

PtichkaEL [24]

Answer:

$22395

Step-by-step explanation:

8 0

3 years ago

Find equation of set of points pieces that its distance from the point 3, 4, -5 and -2, 1, 4 are equal.

Gnesinka [82]

Answer:

Step-by-step explanation:

Suppose we a point $P(x,y,z)$ such that its distance from either the point $A(3,4,-5)$ or $B(-2,1,4)$ is the same.

Using this information we can formula:

distance AP = distance BP

first, let's find the distance from AP, using the distance formula.

$r = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2 + (z_1 - z_2)^2}$

$AP = \sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2}$

similarly, we can find the distance BP

$BP = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

since both distances are exactly the same we can equate them

$AP = BP$

$\sqrt{(3 - x_2)^2 + (4 - y_2)^2 + (-5 - z_2)^2} = \sqrt{(-2 - x_2)^2 + (1 - y_2)^2 + (4 - z_2)^2}$

we can simplify it a bit squaring both sides, and getting rid of the subscripts.

$(3 - x)^2 + (4 - y)^2 + (-5 - z)^2 = (-2 - x)^2 + (1 - y)^2 + (4 - z)^2$

what we have done here is formulated an equation which consists of any point P that will have the same distance from (3,4,-5) and (-2,1,4).

To put it more concretely,

This is the equation of the the plane from that consists of all points (P) from which the distance from both (3,4,-5) and (-2,1,4) are equal.

3 0

3 years ago