Given that sec(θ)=5/3 and θ is in Quadrant I, what is tan(θ)? Write your answer in exact form. Do not round.
1 answer:
9514 1404 393
Answer:
tan(θ) = 4/3
Step-by-step explanation:
The relationship between secant and tangent is ...
1 +tan² = sec²
The the tangent of the angle is ...
tan(θ) = √(sec²(θ) -1)
tan(θ) = √((5/3)² -1) = √(16/9)
tan(θ) = 4/3
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