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Vlad1618 [11]
2 years ago
7

Given that sec(θ)=5/3 and θ is in Quadrant I, what is tan(θ)? Write your answer in exact form. Do not round.

Mathematics
1 answer:
sergeinik [125]2 years ago
7 0

9514 1404 393

Answer:

  tan(θ) = 4/3

Step-by-step explanation:

The relationship between secant and tangent is ...

  1 +tan² = sec²

The the tangent of the angle is ...

  tan(θ) = √(sec²(θ) -1)

  tan(θ) = √((5/3)² -1) = √(16/9)

  tan(θ) = 4/3

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Answer:

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Step-by-step explanation:

The midpoint of two points is the average of the x coordinates and the average of the y coordinates.

Given

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and midpoint is (-7,10)

So, the average of 3 and x is -7, and

the average of -1 and y is 10

We can solve for x first:

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and now solving for y:

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So, the other point B is:

B(-17,21)

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