Answer:
A. 7,348
Step-by-step explanation:
P = le^kt
intitial population = 500
time = 4 hrs
end population = 3,000
So we have all these variables and we need to solve for what the end population will be if we change the time to 6 hours. First, we need to find the rate of the growth(k) so we can plug it back in. The given formula shows a exponencial growth formula. (A = Pe^rt) A is end amount, P is start amount, e is a constant that you can probably find on your graphing calculator, r is the rate, and t is time.
A = Pe^rt
3,000 = 500e^r4
now we can solve for r
divide both sides by 500
6 = e^r4
now because the variable is in the exponent, we have to use a log

ln(6) = 4r
we can plug the log into a calculator to get
1.79 = 4r
divide both sides by 4
r = .448
now lets plug it back in
A = 500e^(.448)(6 hrs) 
A = 7351.12
This is closest to answer A. 7,348
 
        
             
        
        
        
$820.02
Step-by-step explanation:
Since the Taylor family had cash receipts of $876.16 and their excess of cash receipts above cash payments was $56.14. 
The total cash payments for the month will be calculated as:
= $876.16 - $56.14
= $820.02
 
        
             
        
        
        
Answer:
d
Step-by-step explanation:
because its a whole number as in the square root is 4
 
        
             
        
        
        
Volume is a three-dimensional scalar quantity. The number of boxes that can fit in the cargo hold of the truck is 54.
<h3>What is volume?</h3>
A volume is a scalar number that expresses the amount of three-dimensional space enclosed by a closed surface.
The volume of the box = Volume of the cube = a³ = (2.50)³ = 15.625 ft³
The volume of cargo hold = 7.50 × 7.50 × 15 = 843.75 ft³
Now, the number of boxes that can fit in the cargo hold of the truck will be,
Number of boxes = (Volume of truck container)/(Volume of box)
                               = 843.75/15.625
                               = 54
Hence, the number of boxes that can fit in the cargo hold of the truck is 54.
Learn more about Volume:
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