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3 years ago

12

The picture below...

1 answer:

Flura [38]3 years ago

7 0

Answer:

27

Step-by-step explanation:

9+8+10=27

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A new toy hits the local store. Sales (in hundreds) increase at a steady rate for several months, then decrease at about the sam

Montano1993 [528]

Answer:

Option A.

Step-by-step explanation:

It is given that, sales (in hundreds) for several months can be modeled by the function:

$S(m)=-0.625|m-8|+5$

We need to find the month in which 400 toys were sold.

Substitute S(m)=4 in the given function.

$4=-0.625|m-8|+5$

$4-5=-0.625|m-8|$

$-1=-0.625|m-8|$

$\dfrac{-1}{-0.625}=|m-8|$

$1.6=|m-8|$

Now,

$\pm 1.6=m-8$

$1.6=m-8$ or $-1.6=m-8$

$1.6+8=m$ or $-1.6+8=m$

$9.6=m$ or $6.4=m$

Approx the value to the next whole number.

$m\approx 10$ or $m\approx 7$

It means, 400 toys were sold on 7th and 10th month.

Therefore, the correct option is A.

5 0

3 years ago

The expression 3 x 7 - 4x8+2 is equivalent to which of the following?

Mamont248 [21]

Answer: b

explanation: only choice B equals -9 like the given equation.

3 0

3 years ago

Please help answer this question

jasenka [17]

Answer:

9ms

Step-by-step explanation:

4 0

2 years ago

Michelle has x dollars. Tony has nine fewer dollars than Michelle. Drag and drop the expressions into the boxes to write an expr

Radda [10]

your answer is x+9+x

8 0

3 years ago

Read 2 more answers

The annual 2-mile fun-run is a traditional fund-raising event to support local arts and sciences activities. It is known that th

victus00 [196]

Answer: 0.0228

Step-by-step explanation:

Given : The mean and the standard deviation of finish times (in minutes) for this event are respectively as :-

$\mu=30\\\\\sigma=5.5$

If the distribution of finish times is approximately bell-shaped and symmetric, then it must be normally distributed.

Let X be the random variable that represents the finish times for this event.

z score : $z=\dfrac{x-\mu}{\sigma}$

$z=\dfrac{19-30}{5.5}=-2$

Now, the probability of runners who finish in under 19 minutes by using standard normal distribution table :-

$P(X$

Hence, the approximate proportion of runners who finish in under 19 minutes = 0.0228

8 0

2 years ago