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Yuki888 [10]
3 years ago
6

CAN YOU PLEASE HELP ME I WILL DO ANYTHING IF YOU HELP ME PLEASE

Mathematics
1 answer:
Ugo [173]3 years ago
8 0

Answer:

what do you need me to help I can not read the question because it is not visible

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If x=5 and y=7 find the value of x(y-2)<br><br> i need help
lidiya [134]

Answer:

7-2=5  then 5 times 5 is 25 25 is the answer

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A) Find a particular solution to y" + 2y = e^3 + x^3. b) Find the general solution.
Reptile [31]

Answer:

a.P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x}

Step-by-step explanation:

We are given that a linear differential equation

y''+2y=e^{3x}+x^3

We have to find the particular solution

P.I=\frac{e^{3x}}{D^2+2}+\frac{x^3}{D^2+2}

P.I=\frac{e^{3x}}{3^2+2}+\frac{1}{2} x^3(1+\frac{D^2}{2})^{-2}

P.I=\frac{e^{3x}}{11}+\frac{1-2\frac{D^2}{4}+3\frac{D^4}{16}+...}{2}x^3

P.I=\frac{e^{3x}}{11}+\frac{x^3-2\frac{\cdot3\cdot 2x}{4}}{2}+0} (higher order terms can be neglected

P.I=\frac{e^{3x}}{11}+\frac{1}{2}(x^3-3x)

b.Characteristics equation

D^2+2=0

D=\pm\sqrt2 i

C.F=C_1cos \sqrt2x+C_2 sin\sqrt2 x

G.S=C.F+P.I

G.S=C_1Cos \sqrt2 x+C_2 Sin\sqrt2 x+\frac{1}{11}e^{3x}+\frac{1}{2}(x^3-3x)

3 0
4 years ago
Mrs. Rullo has four times as many pens as Mrs. virola. they have a total of 40 pens. How many more pens does Mrs.Rullo have then
IgorLugansk [536]

x + 4x = 40

5x = 40

x = 8

Mrs. Viola has 8 and Mrs. Rullo has 4*8=32 pens.

4 0
3 years ago
Read 2 more answers
Shirley wants to buy a skateboard for $64. She has $98 in her account. She spent $10.85 to buy stationary. She also wants to buy
nikdorinn [45]
She can get 14 cookies
3 0
3 years ago
What is the equation of this graphed line?
pantera1 [17]

Answer:

y = - \frac{1}{3} x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 6, - 3) and (x₂, y₂ ) = (6, - 7)

m = \frac{-7+3}{6+6} = \frac{-4}{12} = - \frac{1}{3}

Note the line crosses the y- axis at (0, - 5) ⇒ c = - 5

y = - \frac{1}{3} x - 5 ← equation of line

4 0
3 years ago
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