We shall use the formula for distance traveled:
s = ut + (1/2)at^2
where
u = initial velocity
t = time
a = acceleration.
Because
u = 0 (car starts from rest),
t = 10 s (travel tme),
a = 2 m/s^2 (acceleration), m
the di mstance traveled is
s = (1/2)*(2 m/s^2)*(10 s)^2 = (1/2)*2*100 = 100
Answer: 100 m
I'm pretty sure the answer is T/LS=x or in other words T divided by LS equals x.
1$ is 100cents
45$ is 4500 cent
THE ORIGINAL price is $53
if 85% = $45
so 15%= ? cross multiply
45x15=85x$
675/85=x$
7.9 app8$ was discounted
original price=45+8=$53
in cent it is 5300 cents
Answer:??? I don't know
Step-by-step explanation:
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9514 1404 393
Answer:
3) x = 9
4) x = 3
Step-by-step explanation:
3) The two short segments are indicated as having a sum equal to the long segment.
(x +2) +(-5 +x) = 15
2x = 18 . . . . . . . . . . . . add 3
x = 9 . . . . . . . . . divide by 2
(This makes the segments be 9+2 = 11 and -5+9 = 4, which total 15.)
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4) Same deal.
3x +3 = 4x
3 = x . . . . . . . . subtract 3x
(This makes the segments be 3(3) = 9 and 4(3) = 12, where 9+3=12.)
