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Leya [2.2K]
3 years ago
14

Step 1: –10 + 8x < 6x – 4

Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

-6/-2<-2x/-2

divide both sides by-2 to remain with the x variable on one side

I hope this helps

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Last week Alice spent $18.25 to bowl 5 games. This week she spent $21.90 to bowl 6 games. Alice owns her bowling balls and shoes
kykrilka [37]

Answer:

Answer

5.0/5

23

Let's find the unit rate stemming from $18 for 4 games:

$18

-------------  =  $4.50/game

4 games

Let's do the same for $27 for 6 games:

$27

------- = $4.50/game (same as before)

 6 g

Thus, the const. of prop. is $4.50/game, and the cost function is

C(x) = ($4.50/game)x, where x is the # of games played.

4 0
3 years ago
What is the missing constant term in the perfect square that starts with x^2+\dfrac{1}{2}xx
grandymaker [24]

Answer:

1/16

Step-by-step explanation:

Given the expression;

x^2+\dfrac{1}{2}x

To find a constant that will make it a perfect square, we will use the square if the half of coefficient of x

Coefficient of x = 1/2

half of Coefficient of x = 1/2*(1/2)

Half of Coefficient of x = 1/4

square of the half of coefficient of x = (1/4)^2

square if the half of coefficient of x = 1/16

hence the constant that will make it a perfect square is 1/16

7 0
3 years ago
We have two stacks of styrofoam cups. One stack has 6 cups, and its height is 15 cm. The other stack has 12 cups, and its height
Irina18 [472]

Complete Question

We have two stacks of styrofoam cups. One stack has 6 cups, and its height is 15 cm. The other stack has 12 cups, and its height is 23 cm. How many cups are needed for a stack with a height of 50 cm

Answer:

37.5 cups

Step-by-step explanation:

Height 1 = 15cm

Number of cups = 6

Height 2 = 23 cm

Number of cups = 12

Hence:

H1 - H2/N1 - N2

= 15 - 23/6 - 12

= -8/-6

= 4/3

The number of cups that are needed for a stack with a height of 50 cm is calculated as:

50 cm ÷ 4/3

= 50 × 3/4

= 37.5 cups

3 0
3 years ago
3n² + 2n - 8=0<br> Solve each equation with the quadratic formula
8_murik_8 [283]

Answer:

-2,4/3

Step-by-step explanation:

ax²+bx+c=0

x=\frac{-b \pm\sqrt{b^2-4ac} }{2a} \\3n^2+2n-8=0\\n=\frac{-2\pm\sqrt{2^2-4*3*(-8)} }{2*3} \\n=\frac{-2 \pm \sqrt{4+96}}{6} }\\n=\frac{-2 \pm 10}{6} \\n=\frac{8}{6} =\frac{4}{3}\\or~n=\frac{-12}{6}=-2

8 0
3 years ago
What transformations change the graph of f(x) to the graph of g(x)?
erica [24]
Shift 5 in along the positive g(x) axis due to the + 5

3 0
3 years ago
Read 2 more answers
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