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Leya [2.2K]
3 years ago
14

Step 1: –10 + 8x < 6x – 4

Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

-6/-2<-2x/-2

divide both sides by-2 to remain with the x variable on one side

I hope this helps

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PLEASE HELP I HAVE AN HOUR LEFT!!
Yuki888 [10]

The statement that correctly describes the horizontal asymptote of g(x) is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the limit of f(x) as x goes to infinity, as long as this value is different of infinity.

In this problem, the function is:

g(x) = \frac{42x^3 - 15}{7x^3 - 4x^2 - 3}

The horizontal asymptote is given as follows:

y = \lim_{x \rightarrow \infty} g(x) = \lim_{x \rightarrow \infty} \frac{42x^3 - 15}{7x^3 - 4x^2 - 3} = \lim_{x \rightarrow \infty} \frac{42x^3}{7x^3} = \lim_{x \rightarrow \infty} 6 = 6

Hence the correct statement is:

Limit of g (x) as x approaches plus-or-minus infinity = 6, so g(x) has an asymptote at y = 6.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0
2 years ago
I NEED HELP PLEASE WHOEVER GIVES RIGHT ANSWER GETS CROWN
crimeas [40]

Answer:

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8 0
3 years ago
Describe the sequence of transformations that would take the graph of f(x)=x² to each parabola described below. Focus: (1/4,0),d
ser-zykov [4K]

Answer:

The parabola obtained is x=y²

Step-by-step explanation:

Given the focus (1/4,0) and directrix: x=-1/4

A point on the parabola is determined by the distance of that point with the focus and with the directrix:

Distance between the parabola and the directrix:\sqrt{(x+\frac{1}{4})^{2}  }

Distance between the parabola and the focus:\sqrt{(x-\frac{1}{4})^{2} +(y-0)^{2} }

\sqrt{(x+\frac{1}{4})^{2}}=\sqrt{(x-\frac{1}{4})^{2} +(y-0)^{2} }

(x+\frac{1}{4})^{2}=(x-\frac{1}{4})^{2} +(y-0)^{2}

x^2+\frac{1}{2} x+\frac{1}{16} = x^2-\frac{1}{2} x+\frac{1}{16} + y^{2}

\frac{1}{2} x=-\frac{1}{2} x + y^{2}

\frac{1}{2} x+\frac{1}{2} x = y^{2}

x=y²

4 0
3 years ago
The radius of a circle is 4 meters. What is the circle's circumference?
IrinaK [193]
<h3>Answer:   Approximately 25.12 meters</h3>

This value is approximate because pi = 3.14 is approximate

===========================================================

Work Shown:

r = 4 = radius

pi = 3.14 approximately

C = circumference

C = 2*pi*r

C = 2*3.14*4

C = 25.12

The circumference is approximately 25.12 meters.

Side note: The circumference is the same as the perimeter of a circle.

4 0
3 years ago
Ram is 1 m 10 cm tall and Shyam is shorter by 20 cm. Find the height of Shyam ​
Vlada [557]

Shyam is 0.9 m

Step-by-step explanation:

10 cm = 10/100 m = 0.1 m

Now,

Ram = 1m + 0.1 m = 1.1 m

Now,

shyam = 1.1 m - 20 cm

= 1.1 m - 20/100 m

= 1.1 m - 0.2 m

= 0.9 m

5 0
3 years ago
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