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3 years ago

0.4 of 1 minute. Help please

Mathematics

2 answers:

Irina-Kira [14]3 years ago

6 0

1 minute is 60 seconds
and 0.4 = 4/10 = 2/5

so find 2/5 of 60 = 24

0.4 of 1 minute is 24 seconds

bearhunter [10]3 years ago

5 0

Answer:

24 seconds

Step-by-step explanation:

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-1/2=3/2k+3/2<br> explain how you got your answer

meriva

-1/2=3/2k+3/2

Rewrite the equation to have k on left side

3/2k+3/2=-1/2

Simplify 3/2k

3k/2+3/2=12

Move all terms not containing k to right side

3k/2=1/2-3/2

3k/2=-2

Multiply both sifmdes by 2

2(3k/2)=-2(2)

3k=-4

Divide both sides by 3 to get k alone

3k/3=-4/3

K= -4/3

5 0

3 years ago

beth is planning a playground and has decided to place the swings in such a way that they are thes same distance from the jungle

NemiM [27]

Answer:

i dont know

Step-by-step explanation:

8 0

2 years ago

Which expressions have a value of 16/81? Check all that apply.

lana [24]

Which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

Answer:

First and last option is correct.

$(\frac{2}{3})^{4}=\frac{16}{81}$

$(\frac{4}{9})^{2}=\frac{16}{81}$

Step-by-step explanation:

Given:

There are four options.

(2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

We need to check all given options for value of 16/81.

Solution:

Using rule.

$(\frac{a}{b})^{n}=\frac{a^{n}}{b^{n}}$

Solve for option $(\frac{2}{3})^4$ .

$(\frac{2}{3})^{4}=\frac{2^4}{3^4}=\frac{2\times 2\times 2\times 2}{3\times 3\times 3\times 3}=\frac{16}{81}$

Solve for option $(\frac{16}{3})^4$ .

$(\frac{16}{3})^{4}=\frac{16^4}{3^4}=\frac{16\times 16\times 16\times 16}{3\times 3\times 3\times 3}=\frac{65536}{81}$

Solve for option $(\frac{4}{81})^2$ .

$(\frac{4}{81})^{2}=\frac{4^2}{81^2}=\frac{4\times 4}{81\times 81}=\frac{16}{6561}$

Solve for option $(\frac{4}{9})^2$ .

$(\frac{4}{9})^{2}=\frac{4^2}{9^2}=\frac{4\times 4}{9\times 9}=\frac{16}{81}$

Therefore, expression $(\frac{2}{3})^4$ and $(\frac{4}{9})^2$ have a value of $\frac{16}{81}$ .

6 0

3 years ago

Please please helpppp.

padilas [110]

There are 3 ways of solving a simultaneous problem, substitution method, elimination method and Gauss-Jordan method. I'm gonna use the substitution method since it's easier and i think it would suit your level more.

First let's try solving for y since it's easier to start with.

Firstly we have to find an equation for x:

$x-2y=2\\x-2y+2y=2+2y\\x=2+2y$

Great, now we can use the substitution method to find the value of y using the first equation:

$2x+3y=11\\2(2+2y)+3y=11\\4+4y+3y=11\\7y=7\\y=1$

Now we know that y=1 we can solve the first equation we made:

$x=2+2y\\x=2+2(1)\\x=4$

And the answer is $x=4 , y= 1\\(4,1)$

Double check:

$2x+3y=11\\2(4)+3(1)=11\\8+3=11\\11=11\\\\x-2y=2\\(4)-2(1)=2\\2=2$

And that's our final answer! (4,1)

7 0

3 years ago

A frustum is made by removing a small cone from a similar large cone in the diagram shown the height of a small cone is a quarte

lesantik [10]

Answer:

Volume of the frustum = ⅓πh(4R² - r²)

Step-by-step explanation:

We are to determine the volume of the frustum.

Find attached the diagram obtained from the given information.

Let height of small cone = h

height of the large cone = H

The height of a small cone is a quarter of the height of the large cone:

h = ¼×H

H = 4h

Volume of the frustum = volume of the large cone - volume of small cone

volume of the large cone = ⅓πR²H

= ⅓πR²(4h) = 4/3 ×π×R²h

volume of small cone = ⅓πr²h

Volume of the frustum = 4/3 ×π×R²h - ⅓πr²h

Volume of the frustum = ⅓(4π×R²h - πr²h)

Volume of the frustum = ⅓πh(4R² - r²)

6 0

3 years ago