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3 years ago

PLEASE HELP ME solve this it due today please fast

Mathematics

1 answer:

Rus_ich [418]3 years ago

3 0

Answer:

5a. 14w

6a. 8b2 - 5b + (-4)

7a. (-3x2) +9x - 4

8a. 3 + 0b

9a. 19 + 6a

Step-by-step explanation: it’s basically imagine that x is :) and y is :( you cant add :( to :) because they are different also the symbols in front of them show if it’s negative or positive

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Help help help help pls help help

Mashcka [7]

It would be 4cm bc the ratio is 2:8 and can be simplified to 1:4

6 0

3 years ago

Determine whether the vectors u and v are parallel, orthogonal, or neither. u = <6, -2>, v = <8, 24>

Leno4ka [110]

Because 6 * 8 + ( - 2 )* 24 = 48 - 48 = 0 , the vectora u and v are orthogonal ;
Two vectors are orthogonal if their dot product is zero.<span />

5 0

4 years ago

Solve the following equations | 3x + 3/7 | = 2 1/3

jasenka [17]

Answer:

X∈ $\frac{5}{63}, -\frac{23}{63}$

Step-by-step explanation:

7 0

3 years ago

Given f(x)=2x^2+3x-5 for what values of x is f(x) positive

kow [346]

Answer:

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

Step-by-step explanation:

we have

$f(x)=2x^{2}+3x-5$

This is a vertical parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The coordinates of the vertex is the point (h,k)

step 1

Find the vertex of the quadratic function

Factor the leading coefficient 2

$f(x)=2(x^{2}+\frac{3}{2}x)-5$

Complete the square

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-5-\frac{9}{8}$

$f(x)=2(x^{2}+\frac{3}{2}x+\frac{9}{16})-\frac{49}{8}$

Rewrite as perfect squares

$f(x)=2(x+\frac{3}{4})^{2}-\frac{49}{8}$

The vertex is the point (-\frac{3}{4},-\frac{49}{8})

step 2

Find the x-intercepts (values of x when the value of f(x) is equal to zero)

For f(x)=0

$2(x+\frac{3}{4})^{2}-\frac{49}{8}=0$

$2(x+\frac{3}{4})^{2}=\frac{49}{8}$

$(x+\frac{3}{4})^{2}=\frac{49}{16}$

take the square root both sides

$x+\frac{3}{4}=\pm\frac{7}{4}$

$x=-\frac{3}{4}\pm\frac{7}{4}$

$x_1=-\frac{3}{4}+\frac{7}{4}=1$

$x_2=-\frac{3}{4}-\frac{7}{4}=-2.5$

therefore

The function f(x) is negative in the interval (-2.5,1)

The function f(x) is positive in the interval (-≠,-2.5) ∪ (1,∞)

see the attached figure to better understand the problem

6 0

4 years ago

What is the slope of a line parallel to the line whose equation is 5x - 3y = 1<br><br> PLS HELP!

madam [21]

Parallel lines refers to a pair of straight lines that never intercept or touch each other. The slopes of this lines is the same one.

On this exercise is given the equation of a line, and is asked to find the slope of a line that is parallel to the given one.

5x-3y=1 Subtract 5x in both sides
-3y=-5x+1 Divide by -3 in both sides to isolate y
y=5/3x-1/3

The slope of the given line, 5x-3y=1, is 5/3, which means that the slope of a line parallel to this one, would be 5/3.

4 0

3 years ago

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