<u>Answer:</u>
Cost of package of paper = 4$
Cost of stapler = 7$
<u>Explanation:</u>
Consider the cost of package of paper = x and that of stapler = y.
Now, we are given that cost of 3 paper packages and 4 staplers = 40$
Hence we get, 3x + 4y = 40 as 1st equation.
we are also given, cost of 5 paper packages and 6 staplers = 62$
Hence, the second equation is 5x + 6y = 62
Now, solving the two equations by method of elimination, we first equate coefficients of any one variable say x by multiplying 1st equation by 5 and second by 3 we get ->
15x + 20y = 200
15x + 18y= 186
Subtracting the two we get y = 7 and substituting this value of y in first equation we get x = 4
which gives the required cost of one paper package = x = 4$
and one stapler = y = 7$
Answer:
The answer is {36}
Step-by-step explanation:
I took the quiz hope this helps
Answer:
SA = 2520 ft^2
Step-by-step explanation:
a = 21ft
b = 29ft
c = 20ft
h = 30ft
SA = 2
+ (a+b+c)h
= s(s﹣a)(s﹣b)(s﹣c)
s = 
SA= ah + bh + ch + 
SA= (21 * 30) + (29 * 30) + (20 * 30) +
SA = 2520 ft^2
Get like terms together. you might have to move across the equals sign
3x-x=-6+82
2x=76
x=38
Step-by-step explanation:
-13=4v+8-7v
-13-8=-3v
3v=21
v=7
