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never [62]
3 years ago
11

Which function of a web page relies on responsive web design? Adding extra horizontal scroll Blocking mobile devices from viewin

g Eliminating extra links Resizing content to fit a screen
Computers and Technology
2 answers:
Alex_Xolod [135]3 years ago
4 0

Answer:

Resizing content to fit a screen

Explanation:

Responsive means a website that is able to adapt its contents to the size of the device used for viewing.

galina1969 [7]3 years ago
4 0

Answer:

Resizing content to fit a screen

Explanation:

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What are the pros and cons of MP3 audio archives?
UkoKoshka [18]
Was this in reference to literal audio archives? If so, I don't see any cons beside possible copyright infringement.

If you're talking about the codecs themselves, then I can do that.

<span>Pros:

</span>- Widespread acceptance. Supported in nearly all hardware devices, and continually adopted by newer ones.

- Faster decoding. Much more so than FLAC, Vorbis, etc.

- Relaxed licensing schedule.

<span>Cons:
</span><span>
</span>- Lower quality and efficiency than most modern codecs. (To be fair, never really noticed this one).

- Sometimes the maximum bitrate isn't enough.

- Pretty much void/unusable for high definition audio (higher than <span>48kHz).</span>

 
7 0
3 years ago
To find the area, Andrea tiled a rectangle and sketched her answer. Sketch Andrea's rectangle, and find the area. Show your mult
seraphim [82]

Answer:

Area = 6.25

Explanation:

Given

Length = 2.5

Width = 2.5

See attachment for rectangle

Required

Determine the area of the rectangle

Area is calculated as:

Area = Length * Width

This gives:

Area = 2.5 * 2.5

Area = 6.25

<em>The area of Andrea's sketch is 6.25</em>

8 0
2 years ago
You trained a binary classifier model which gives very high accuracy on thetraining data, but much lower accuracy on validation
kompoz [17]

Answer:

a. This is an instance of overfitting.

Explanation:

In data modeling and machine learning practice, data modeling begins with model training whereby the training data is used to train and fit a prediction model. When a trained model performs well on training data and has low accuracy on the test data, then we say say the model is overfitting. This means that the model is memorizing rather Than learning and hence, model fits the data too well, hence, making the model unable to perform well on the test or validation set. A model which underfits will fail to perform well on both the training and validation set.

4 0
3 years ago
Comptel, a world leader in computer hardware, differentiates itself from its customers by providing excellent after-sales servic
nignag [31]
❤️The answer is supply chain effectiveness.


Hope you have a great day!
4 0
3 years ago
The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a
Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0
3 years ago
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