Answer:
Option (1)
Step-by-step explanation:
Given:
CF ≅ DF
CE ≅ DE
To prove:
ΔCFE ≅ ΔDFE
Solution:
From ΔCFE and ΔDFE,
Statements Reasons
1). CF ≅ DF 1). Given
2). CE ≅ DE 2). Given
3). FE ≅ FE 3). Reflexive property
4). ΔCFE ≅ ΔDFE 4). By SSS property of congruence
Therefore, SSS postulate of congruence will be the answer.
Option (1) will be the answer.
To set up consecutive even integers you use x for the first integer and x + 2 for the second integer. You add 2 since you are going to the next EVEN instead of just the next integer. Now we set up an equation = 798 and solve.
x + x + 2 = 798
2x + 2 = 798
subtract -2 from both sides
2x = 796
divide by 2 on both sides
x = 398
x + 2 = 398 + 2 = 400
CHECK 398 + 400 = 798
For this case we have that, by definition, the equation of a line in the slope-intersection form is given by:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Where:
m: It's the slope
b: It is the cutting point with the y axis
We have, according to the statement data that:
![m = - \frac {2} {3}](https://tex.z-dn.net/?f=m%20%3D%20-%20%5Cfrac%20%7B2%7D%20%7B3%7D)
So, the equation is of the form:
![y = - \frac {2} {3} x + b](https://tex.z-dn.net/?f=y%20%3D%20-%20%5Cfrac%20%7B2%7D%20%7B3%7D%20x%20%2B%20b)
We also have that the line intersects the "x" axis at -3, that is, the line passes through the point ![(x, y): (- 3,0)](https://tex.z-dn.net/?f=%28x%2C%20y%29%3A%20%28-%203%2C0%29)
We substitute to find "b":
![0 = -\frac {2} {3} (- 3) + b\\0 = -2 + b\\b = 2](https://tex.z-dn.net/?f=0%20%3D%20-%5Cfrac%20%7B2%7D%20%7B3%7D%20%28-%203%29%20%2B%20b%5C%5C0%20%3D%20-2%20%2B%20b%5C%5Cb%20%3D%202)
Finally, the equation is of the form:
![y = - \frac {2} {3} x + 2](https://tex.z-dn.net/?f=y%20%3D%20-%20%5Cfrac%20%7B2%7D%20%7B3%7D%20x%20%2B%202)
Answer:
![y = - \frac {2} {3} x + 2](https://tex.z-dn.net/?f=y%20%3D%20-%20%5Cfrac%20%7B2%7D%20%7B3%7D%20x%20%2B%202)
It’s x=0 isn’t it that answer
Answer:
60.
Step-by-step explanation:
Go by the formula in the picture