Answer:
70 degrees
Step-by-step explanation:
Angle HMK = 50 degrees
Angles LMK, MLK and MKL are equal to 60 degrees, being in a perfectly congruent triangle which they all add up to 180 degrees.
Add 60 to 50 = 110
180 - 110 = 70 degrees, equal to angle HMG.
This is because the line that angles LMK, HMK and HMG are on is supplementary.
Answer:
33%
Step-by-step explanation:
sorry my bad i did percentage increase.
Answer:
131 and 49
Step-by-step explanation:
Supplementary angle means 180° when all angles are added together.
First angle: (x + 82)
Second angle: x
(x + 82) + x = 180
2x + 82 = 180
2x = 98
x = 49
First angle: 49 + 82 = 131°
Second angle: 49°
Answer:
B. 
Step-by-step explanation:
Let p be number of points Michael needs to score in 2nd game to catch up.
We have been given that Janet scored 200 and 400 points in the first 2 rounds of a computer game. So the total points scored by Janet in two games will be:
points.
We are also told that Michael had scored 250 points in the first round and he want to get the same total score as Janet.
So we can find the number of points Michael needs to score to catch up Janet by subtracting the number of points scored by Michael in 1st game from total number of points scored by Janet in two games. We can represent this information in an equation as:

Therefore, the equation
will help Michael to find the number of points he need to catch up Janet and option B is the correct choice.
Answer:

Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner
is:

where :
(a and b are the length and the breath of the rectangle respectively )


![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)

Thus; the moment of inertia of the lamina about one corner is 