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3 years ago

Order these values from least to greatest.

Mathematics

2 answers:

liubo4ka [24]3 years ago

3 0

Answer:

1 . 16

2 . 4

3 . 64

4 . -4

The fourth one goes first and then the second one and then the first one and then the third one.

tia_tia [17]3 years ago

3 0

1.16 2.4 3.64 4.-4 the order is -4, 4, 16, 64

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DiKsa [7]

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What is this what grade are you in

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2 years ago

Five individuals from an animal population thought to be near extinction in a certain region have been caught, tagged, and relea

Talja [164]

Answer:

a) For this case the random variable X follows a hypergometric distribution.

b) $E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c) $P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d) $P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

Step-by-step explanation:

The hypergometric distribution is a discrete probability distribution that its useful when we have more than two distinguishable groups in a sample and the probability mass function is given by:

$P(X=k)= \frac{(MCk)(N-M C n-k)}{NCn}$

Where N is the population size, M is the number of success states in the population, n is the number of draws, k is the number of observed successes

The expected value and variance for this distribution are given by:

$E(X)= n\frac{M}{N}$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}$

a. What is the distribution of X?

For this case the random variable X follows a hypergometric distribution.

b. Compute the values for E(X) and Var(X)

For this case n=10, M=5, N=25, so then we can replace into the formulas like this:

$E(X)= n\frac{M}{N}=10 \frac{5}{25}=2$

$Var(X)=n \frac{M}{N}\frac{N-M}{N}\frac{N-n}{N-1}=10\frac{5}{25}\frac{25-5}{25}\frac{25-10}{25-1}=1$

c. What is the probability that none of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=0)= \frac{(5C0)(25-5 C 10-0)}{25C10}=\frac{1*184756}{3268760}=0.0565$

d. What is the probability that all of the animals in the second sample are tagged?

So for this case we want this probability:

$P(X=5)= \frac{(5C5)(25-5 C 10-5)}{25C10}=\frac{1*15504}{3268760}=0.00474$

4 0

4 years ago

(x) = 3х + 7<br> g(x) 2x + 12

AlekseyPX

What are you trying to do with this/solve for?

6 0

4 years ago

The next two systems do NOT have opposite like terms

Sindrei [870]

Answer:

x = 10

y = 6

Step-by-step explanation:

Multiply second equation with -1 and then add it up with first equation

(-1)*(6x - 7y) = 18

-6x + 7y = -18

6x - 6y - 6x + 7y = 24 - 18 add like terms

y = 6 to find the value of x use this information

6x - 6y = 24 replace y with 6

6x - 6*6 = 24

6x - 36 = 24 add 36 to both sides

6x = 60 divide both sides by 6

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2 years ago

Why does the margin of error increase as the level of confidence increases? Choose the correct answer below. A. The margin of e

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Answer:

The margin of error increases as the level of confidence increases because the larger the expected proportion of intervals that will contain the parameter, the larger the margin error.

Step-by-step explanation:

Margin of Error is a statistical measure of random sampling error insurvey results.

Level of confidence reflects percentage range around sample mean, that can be expected to contain population actual parameter.

High level of confidence means larger range band of confidence interval, supposed to contain the population parameter. This further implies high expected variation between sample statistic & actual parameter i.e Margin Error increases.

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3 years ago