Answer:
131.95888888888888
Step-by-step explanation:
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Based on the measurements of the pool and the path of uniform width, the area of the width and length of the path can be found to be 28.8 meters.
<h3>How to find the width and length?</h3>
First, find the area of the pool:
= Length x Width
= 10 x 26
= 260 meters ²
The area of the path can therefore be found to be:
= Total area of pool and path combined - Area of pool
= 1,092 - 260
= 832 meters²
Seeing as the path has uniform width, that means that the width is the same and the length so the width and length of the pool is:
= √area of the path
= √832
= 28.8
In conclusion, the width and length of the path are 28.8 meters.
Find out more on combined area at brainly.com/question/12966430
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Answer:
Sam is incorrect
Step-by-step explanation:
We can calculate the lengths of the diagonals using Pythagoras' identity.
The diagonals divide the rectangle and square into 2 right triangles.
Consider Δ SRQ from the rectangle
SQ² = SR² + RQ² = 12² + 6² = 144 + 36 = 180 ( take square root of both sides )
SQ = 
≈ 13.4 in ( to 1 dec. place )
Consider Δ ONM from the square
OM² = ON² + NM² = 6² + 6² = 36 + 36 = 72 ( take square root of both sides )
OM = 
≈ 8.5 in ( to 1 dec. place )
Now 2 × OM = 2 × 8.5 = 17 ≠ 13.4
Then diagonal OM is not twice the length of diagonal SQ
250 + 100 = 350
350 + 1000 = 1350
1350 / 5 = 270
they need to sell 270 tickets
answer is B
Answer:
a. m = Vd
b. 6.012g
Step-by-step explanation:
a. you need to rearrange the equation so that you're solving for m. you can do so by multiplying both sides by V so you end up with
Vd = m or m = Vd (i prefer writing it this was purely cause it looks better)
b. now, you can plug in each value into the new equation so you get
5.01g/cm3 x 1.2 cm3 = m
from here you just multiply as normal
