I don’t know The answer but I tried
Given:
let h be the high quality bean
let c be the cheaper bean
h + c = 160
6h + 3.25c = 160*4.97
6h + 3.25c = 795.20
h = 160 - c
6(160 - c) + 3.25c = 795.20
960 - 6c + 3.25c = 795.20
-2.75c = 795.20 - 960
-2.75c = -164.80
c = -164.80 / -2.75
c = 59.92 or 60 lbs
h = 160 - c
h = 160 - 60
h = 100 lbs
Sarah should blend 60 lbs of cheap coffee bean and 100 lbs of high quality coffee bean.
Answer:
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Answer:f(g(0))= 1/5
g(f(0))= 7
Step-by-step explanation:
for f(g(0))=you solve for g(x) but you plug in 0 for x so g(0)= 8(0)+3
=3
so now you plug in the answer of the function of g(x) witch is 3 and plug it in as the x for F(x) so f(3)= 1/(3)+2
= 1/5
so f(g(0)) is equal to 1/5
Now for G(f(0)) you solve for f(x) by pluging 0 for x so F(0)= 1/(0)+2
=1/2
now you plug in 1/2 for the x of g(x) so g(1/2)= 8(1/2)+3
= 4+3
=7
so g(f(0)) is equal to 7
Hope this helps:)
