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raketka [301]
3 years ago
15

Michael is 2 years older than his friend Jason. 16 years ago, Jason was half of Michael's age. how old is Jason now?

Mathematics
1 answer:
zysi [14]3 years ago
6 0

Answer:

The present age of Jason is 18 years.

Step-by-step explanation:

Let the present age of Jason be x years.

Michael is 2 years older than Jason.

So, the present age of Michael be x+2 years.

16 years ago,

Jason's age =x-16 years.

Michael' age =x+2-16=x-14 years.

According to the question, 16 years ago, Jason was half of Michael's age.

So, x-16=\frac{1}{2}(x-14)

\Rightarrow 2\left ( x-16 \right )=(x-14)

\Rightarrow 2x-32=x-14

\Rightarrow 2x-x=-14+32

\Rightarrow x=18

Hence, the present age of Jason is 18 years.

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Please help out and if you know help me show work ??
Ghella [55]

Answer:  14

<u>Step-by-step explanation:</u>

Consecutive even numbers would be {2, 4, 6, 8, 10, ...}

Let x represent the smallest number, then x + 2 is the middle number and x + 4 is the largest number.

1st number: x

2nd number: x + 2

3rd number: x + 4

1st number + 2nd number + 3rd number = Sum

      (x)        +      (x + 2)       +      (x + 4)      =  48

                                                      3x + 6   =  48

                                                      3x          = 42

                                                        x           = 14

1st number: x           ⇒ x = 14

2nd number: x + 2   ⇒ 14 + 2 = 16

3rd number: x + 4    ⇒ 14 + 4 = 18

<u>Check:</u>

14 + 16 + 18 = 48 \checkmark

 

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2 years ago
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