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Tems11 [23]
3 years ago
7

What function represents exponential decay?

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

There are two types of exponential functions: exponential growth and exponential decay. In the function f (x) = bx when b > 1, the function represents exponential growth. In the function f (x) = bx when 0 < b < 1, the function represents exponential decay.

Step-by-step explanation:

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IRISSAK [1]

72 if * is exponents

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3 years ago
Rearrange the following equation to solve for x. y=1/2x+10
maxonik [38]
In order to solve this we must first,


Subtract both sides of the equation by 10,
y-10=1/2x

Now we have to multiply both sides by 2 so that only x is left.

2y-20=x


Therefore, x=2y-20
6 0
3 years ago
If 18 is more than 2 times a number is -10, what is the number
AleksAgata [21]

Answer:

-14

Step-by-step explanation:

-10-18=-28 -28/2=-14

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3 years ago
AC=3x+3, AB=-1+2x, and BC=11 find x
Nikolay [14]

Answer:

the Value of x is 7.

Step-by-step explanation:

5 0
2 years ago
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
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