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Natasha2012 [34]
3 years ago
13

In an examination every student took history or geography or both of 500 candidates 60% took history whiles 72% took geography.

How many students took both subjects
Mathematics
2 answers:
almond37 [142]3 years ago
6 0

Answer:

80 students

Step-by-step explanation:

NeTakaya3 years ago
3 0

Answer:

80

Step-by-step explanation:

60% of 500 = 300

72% of 500 = 360

40% of 500 = 200

28% of 500 = 140

300+360 = 660

660 - 2x = 500

660 - 500 = 2x

160 = 2x

2x = 160

x = 80

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<u><em>The answer is c, hope this helps</em></u>

Step-by-step explanation:

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FrozenT [24]
A polynomial asymptote is a function p(x) such that

\displaystyle\lim_{x\to\pm\infty}(f(x)-p(x))=0

(y+1)^2=4xy\implies y(x)=2x-1\pm2\sqrt{x^2-x}

Since this equation defines a hyperbola, we expect the asymptotes to be lines of the form p(x)=ax+b.

Ignore the negative root (we don't need it). If y=2x-1+2\sqrt{x^2-x}, then we want to find constants a,b such that

\displaystyle\lim_{x\to\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

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\sqrt{x^2-x}=\sqrt{x^2}\sqrt{1-\dfrac1x}
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since x\to\infty forces us to have x>0. And as x\to\infty, the \dfrac1x term is "negligible", so really \sqrt{x^2-x}\approx x. We can then treat the limand like

2x-1+2x-ax-b=(4-a)x-(b+1)

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-\dfrac12=\dfrac{b+1}2\implies b=-2

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\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-ax-b)=0

\displaystyle\lim_{x\to-\infty}(2x-2x\sqrt{1-\frac1x}-ax-(b+1))=0

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\displaystyle\lim_{x\to-\infty}(2x-1+2\sqrt{x^2-x}-b)=0

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(x+\sqrt{x^2-x})\cdot\dfrac{x-\sqrt{x^2-x}}{x-\sqrt{x^2-x}}=\dfrac{x^2-(x^2-x)}{x-\sqrt{x^2-x}}=\dfrac&#10; x{x-(-x)\sqrt{1-\frac1x}}=\dfrac1{1+\sqrt{1-\frac1x}}

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3 years ago
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Answer:

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If there are 189 children, then there are 189 divided 7 = <em>27 groups of 7 children.</em>

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