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2 years ago

9

A 26-year-old male buys 100/300/100 liability insurance, collision insurance with a $100 deductible, and comprehensive insurance

with a $250 deductible What is his total annual premium? Liability Insurance Type Bodily injury Amount Premium 25/50 $220 50/100 $310 100/300 $450 25 $175 50 $245 100 $375 Property damage Collision & Comprehensive Premiums Deductible Collision Comprehensive $215 $129 $250 $185 $102 $500 $148 $85 $100 Rating Factor a Male 3.0 Female 1.45 Age 17-20 21-24 25-29 1.2 215 1.55 1.0 $1142.00 $1765.45 $1770.10 $1785.25

1 answer:

lesantik [10]2 years ago

7 0

Correct me if I’m wrong, I believe you have to add all of those numbers together. Then divide after and plug in those remaining digits

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Imagine you have a classmate who has never had an introduction to statistics in a math course. Explain to that person how the pr

Tamiku [17]

Answer:

Probability of selecting red tile out of a box containing 3 red,2 white & 5 black tiles = 3/10 = 0.3

Step-by-step explanation:

Probability is the calculation of likelihood of an event.

It can be calculated by Formula : Favourable outcome / Total Outcomes

Example : If a box contain 3 red tiles, 2 white tiles, 5 black tiles

Prob (selecting a red tile) = Favourable outcome (red tiles) / Total Outcomes (total tiles) = 3 / 10 = 0.3

Similarly, prob (white tile) & prob (black tile) = 2/10 ie 0.2 & 5/10 ie 0.5 respectively

8 0

3 years ago

Pls show work! questions on pic

Lena [83]

Answer:

a.(10,23)

b.(7,30)

e.(20,20)

Step-by-step explanation:

We are given that

x=Width of garden

y=Length of garden

According to question

$x\geq 5$

$y\geq 20$

Perimeter of rectangle= $2(x+y)$

Where x=Width of rectangle

y=Length of rectangle

Fencing used = $2(x+y)$

$2(x+y)\leq 80$

First we change inequality into equality

$x=5$ ...(1)

$y=20$ ...(2)

$2(x+y)=80$

$x+y=40$ ...(3)

Substitute x=0 in equation (3)

$y=40$

Substitute y=0 in equation (3)

$x=40$

Substitute x=0 and y=0 in equation (3)

$2(x+y)\leq 80$

$0\leq 80$

It is true. Therefore, the shaded region below the line.

$0\geq 5$

$0\geq 20$

These are false equation .Therefore, the shaded region above the line.

Substitute x=5 in equation (3)

$5+y=40$

$y=40-5=35$

Substitute y=20 in equation (3)

$x+20=40$

$x=40-20=20$

Intersection point of equation (1) and (3) is (5,35) and intersect point of equation (2) and (3) is (20,20).

Now,

a.(10,23)

Substitute in

$2(x+y)\leq 80$

$2(10+23)\leq 80$

$66\geq 80$

10>5 and 23>20

it satisfied all inequality.

Hence, it is a solution.

b.(7,30)

7>5

30>20

$2(7+30)=74$

it satisfied all inequality.

Hence, it is a solution.

c.(18,25)

18>5

25>20

$2(18+25)=86>80$

It does not satisfied third inequality

Hence, it is not a solution.

d.(8,35)

8>5

35>20

$2(8+35)=86>80$

It does not satisfied third inequality

Hence, it is not a solution.

e.(20,20)

$2(20+20)=80$

20>5

20=20

it satisfied all inequality.

Hence, it is a solution.

4 0

3 years ago

What is the equation of the function graphed below?

Andreas93 [3]

Answer:

D

Step-by-step explanation:

sorry if the answer is wrong

5 0

2 years ago

Nine tenths minus one third

Shtirlitz [24]

I think you want to write it

so it's:

9-1/3

4 0

3 years ago

Read 2 more answers

Find the missing side length. Round your answer to the nearest tenth.

EastWind [94]

Answer:

5.545

Step-by-step explanation:

This problem can be easily solved by using the law of cosines, which relates the lengths of the sides of a triangle to the cosine of one of its angles.

in this case, the formula can be applied in the following way

a^2 = b^2 + c^2 - 2*b*c*cos(α)

Where

a,b,c are each of the sides of the triangle,

α is the angle between sides b and c

(See attached picture)

If we use the formula we get

a^2 = (9)^2 + (6)^2 - 2*(9)(6)*cos(37°)

a^2 = 81 + 36 - 86.2526

a^2 = 30.747

a = sqrt(30.747)

a = 5.545

5 0

3 years ago