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Serhud [2]
3 years ago
9

A 26-year-old male buys 100/300/100 liability insurance, collision insurance with a $100 deductible, and comprehensive insurance

with a $250 deductible What is his total annual premium? Liability Insurance Type Bodily injury Amount Premium 25/50 $220 50/100 $310 100/300 $450 25 $175 50 $245 100 $375 Property damage Collision & Comprehensive Premiums Deductible Collision Comprehensive $215 $129 $250 $185 $102 $500 $148 $85 $100 Rating Factor a Male 3.0 Female 1.45 Age 17-20 21-24 25-29 1.2 215 1.55 1.0 $1142.00 $1765.45 $1770.10 $1785.25​
Mathematics
1 answer:
lesantik [10]3 years ago
7 0
Correct me if I’m wrong, I believe you have to add all of those numbers together. Then divide after and plug in those remaining digits
You might be interested in
Please help me answer this question
Jlenok [28]

Answer:c

Step-by-step explanation:

4/3 times pi times 7 cubed

5 0
3 years ago
What is the answer plz help!!!
romanna [79]

9514 1404 393

Answer:

  B.  horizontal stretch by a factor of 3

Step-by-step explanation:

Replacing x by x/k in a function causes its graph to be stretched horizontally by a factor of k. (This makes sense because it means x needs to be k times as large to give the same argument to the function.)

Here, the value of k is 3, so the function graph is horizontally stretched by a factor of 3.

4 0
3 years ago
The desired percentage of Silicon Dioxide (SiO2) in a certain type of aluminous cement is 5.5. To test whether the true average
Reil [10]

Answer:

a)  Null hypothesis : H₀ : μ = 5.5

 Alternative Hypothesis : H₁ : μ < 5.5

b) The test statistic

        |t| = |-3.33| = 3.33

c) P - value lies between in these intervals

0.001 < P < 0.005

Step-by-step explanation:

<u><em>Step( i )</em></u>:-

Given data the Population mean 'μ' = 5.5

The small sample size 'n' = 16

The sample mean (x⁻) = 5.25

Given the  percentage of SiO2 in a sample is normally distributed with a sigma of 0.3.

<u><em> Null hypothesis : H₀ : μ = 5.5</em></u>

<u><em>  Alternative Hypothesis : H₁ : μ < 5.5</em></u>

 Level of significance ∝ = 0.01

<u><em>Step(ii)</em></u>:-

 The test statistic

                              t = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }

                             t = \frac{5.25 -5.5}{\frac{0.3}{\sqrt{16} } }

On calculation , we get

                            t = -3.33

                           |t| = |-3.33| = 3.33

<u><em>Step(iii)</em></u>:-

<u><em>P - value</em></u>

<u><em>The degrees of freedom γ = n-1 = 16-1 =15</em></u>

The calculated value t = 3.33 (check t-table) lies between the 0.001 to 0.005

0.001 < P < 0.005

<u>Condition(i)</u>

P - value < ∝ then reject H₀

<u>Condition(ii)</u>

P - value > ∝ then Accept H₀

we observe that  0.001 < P < 0.005

P- value < 0.01

we rejected  H₀

<em>(or)</em>

The tabulated value  = 2.60 at 0.01 level of significance with '15' degrees of freedom

The calculated value t = 3.33 > 2.60 at 0.01 level of significance with '15' degrees of freedom

The null hypothesis is rejected

<u><em>Conclusion</em></u>:-

Accepted Alternative hypothesis H₁

The Claim that the true average is smaller than 5.5

<u><em></em></u>

             

4 0
3 years ago
What is the y-coordinate of point D after a translation of (x, y) → (x + 6, y – 4)?
fiasKO [112]

The y - coordinate of D after a translation is 1

Explanation:

The point D after a translation is given by $(x, y) \rightarrow(x+6, y-4)$

The y - coordinate of the point D is 5.

Now, we shall determine the value of the y - coordinate of D after the translation $(x, y) \rightarrow(x+6, y-4)$

Let us consider the y - coordinate of D' and D

Thus, we have,

y-4=5

Subtracting both sides by 4, we get,

y=1

Thus, the y - coordinate of D after a translation is 1

7 0
3 years ago
Eric says he knows 9/10 is 1/10 less than 10/10 or 1 mile so he is going to subtract 1 mile then I had 1/10 back can he use this
Anon25 [30]
He can, if he subtracts the 1/10 from 10/10 or 1 he will have 9/10.. hope it helped
7 0
3 years ago
Read 2 more answers
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