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Serhud [2]
3 years ago
9

A 26-year-old male buys 100/300/100 liability insurance, collision insurance with a $100 deductible, and comprehensive insurance

with a $250 deductible What is his total annual premium? Liability Insurance Type Bodily injury Amount Premium 25/50 $220 50/100 $310 100/300 $450 25 $175 50 $245 100 $375 Property damage Collision & Comprehensive Premiums Deductible Collision Comprehensive $215 $129 $250 $185 $102 $500 $148 $85 $100 Rating Factor a Male 3.0 Female 1.45 Age 17-20 21-24 25-29 1.2 215 1.55 1.0 $1142.00 $1765.45 $1770.10 $1785.25​
Mathematics
1 answer:
lesantik [10]3 years ago
7 0
Correct me if I’m wrong, I believe you have to add all of those numbers together. Then divide after and plug in those remaining digits
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What is <br>34<br>8<br>fraction whole number, or mixed number​
bogdanovich [222]

Answer:

34/8 would equal to 4 1/4 (simplified)

Hope this helps!

8 0
3 years ago
Read 2 more answers
Plutonium-240 decays according to the function L where o
PIT_PIT [208]

Answer:

\boxed{\textbf{1700 yr}}

Step-by-step explanation:

-\dfrac{\text{d}L}{\text{d}t} = kL\\\\\dfrac{dL}{L}=-kdt\\\\\ln L = -kt + C\\\text{At t = 0, L = L$_{0}$, so C = $\ln L_{0}$}\\\ln L = -kt + \ln L_{0}\\\ln L_{0} - \ln L = kt\\\\\ln \dfrac{L_{0}}{L} =kt

Data:

L₀ = 24 g

L = 20 g

k = 0.000 11 yr⁻¹

Calculation:

\ln \dfrac{24}{20} =0.000 11t\\\\\ln 1.2 = 0.000 11t\\\\0.1823 = 0.000 11t\\\\t = \dfrac{0.1823}{0.000 11} = \textbf{1700 yr}\\\\\text{It will take } \boxed{\textbf{1700 yr}}\text{ for the polonium to decay to 20 g}

8 0
3 years ago
In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track
Aloiza [94]

Answer:

Approximately 0.31\; \rm m, assuming that g = 9.81\; \rm N \cdot kg^{-1}.

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned} .

Weight of the slide:

\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}.

Normal force between the sled and the slope:

\begin{aligned}F_{\rm N} &= W\cdot  \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}.

Calculate the kinetic friction between the sled and the slope:

\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}.

Assume that the sled and its passenger has reached a height of h meters relative to the base of the slope.

Gain in gravitational potential energy:

\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}.

Distance travelled along the slope:

\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}.

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}.

In other words, the sled and its passenger would have lost (approximately) ((137 + 68.1)\, h)\; {\rm J} of energy when it is at a height of h\; {\rm m}.

The initial amount of energy that the sled and its passenger possessed was \text{KE} = 63\; {\rm J}. All that much energy would have been converted when the sled is at its maximum height. Therefore, when h\; {\rm m} is the maximum height of the sled, the following equation would hold.

((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}.

Solve for h:

(137 + 68.1)\, h = 63.

\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}.

Therefore, the maximum height that this sled would reach would be approximately 0.31\; \rm m.

7 0
3 years ago
A wallet sized picturer measures 1/6 and 1/4 what is the area
kirza4 [7]

Answer:

A = 1/24

Step-by-step explanation:

Area is the length times the width

A = l*w

The length is 1/6 and width is 1/4

A = 1/6*1/4

A = 1/24

7 0
4 years ago
ILL GIVE BRAINLIEST IF CORRECT
dangina [55]
There the answer is A the range is none negative
6 0
3 years ago
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