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nikklg [1K]
2 years ago
13

juan has three blue shirts, two green shirts, 7 red shirts, and five pairs of pants, and two pairs of khaki pants. How many diff

erent outfuts consisting of one shirt and one pair of pants are possoble?
Mathematics
1 answer:
Umnica [9.8K]2 years ago
5 0

Answer:

Step-by-step explanation:

7 x 5 is 35. 7 x 2 is 14. 14 + 35 is 49

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Is a vertical line a function
topjm [15]

Answer:

No

Step-by-step explanation:

Explanation 1)A vertical line can be represented by the equation x=a, where a can be any number. If you think about it, there is no y in the function, this making it not a function.

Explanation 2) For a line to be a function it has to pass the vertical line test, so you will draw a vertical line through the function and if it touches more than one point then it is not a function. In this case if you draw a vertical line through a vertical line there are an infinite number of places where the lines intercept, so it is not a function.

4 0
2 years ago
Read 2 more answers
PLZ SOMEONE HELP ME THIS IS URGENT AND MY MATH TEACHER IS REALLY STRICT PLZ HELP???
Zepler [3.9K]

Answer:

a:

-4 + (-7)

b:

-4+7

Step-by-step explanation:

here sorry it took so long

3 0
2 years ago
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Help me<br> On this pleaseee
Evgen [1.6K]
2 rectangle shaped
1) Length = 160 mi ; Width = 40 mi
2) Length = 440 mi - 160 mi ; Width = 240 mi - 70 mi

1 triangle shape
1) base = 70 mi ; height = 440 mi - 160 mi

Area Rectangle 1 = 160 mi * 40 mi = 6,400 mi²
Area Rectangle 2 = 280 mi * 170 mi = 47,600 mi²
Area Triangle 1 = ((440 mi - 160 mi) * 70mi)/2 = (280mi * 70mi)/2 = 9,800 mi²

Total Area = 6,400 mi² + 47,600 mi² + 9,800 mi² = <span>63,800 mi²</span>
4 0
3 years ago
Find a power series representation of e^x sin(x)
liberstina [14]
The Taylor series is defined by:
f(x) = \sum \frac{f^n (a)}{n!} (x-a)^n

Let a = 0.
Then its just a matter of finding derivatives and determining how many terms is needed for the series.

Derivatives can be found using product rule:
f^n (x) = e^x g^{n-1} (x) + e^x g^n (x)  \\ g^0 (x) = sin x

Do this successively to n = 6.
f^1 (x) = e^x (sinx +cos x) \\ f^2 (x) = e^x (2cos x)  \\ f^3 (x) = e^x(2cos x - 2sin x)  \\ f^4 (x) = e^x (-4 sin x)  \\ f^5 (x) = e^x(-4sinx -4cos x) \\ f^6(x) = e^x(-8cos x)

Plug in x=0 and sub into taylor series:
e^x  sin x = x+x^2 +\frac{x^3}{3} -\frac{x^5}{30}-\frac{x^6}{90}...

If more terms are needed simply continue the recursive derivative formula and add to taylor series.
6 0
3 years ago
Please help me. This is due tomorrow
IRISSAK [1]
The picture is upside down my dude, delete the question, re-upload it and ill help you out.
3 0
2 years ago
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