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3 years ago

Please help me with this question

Mathematics

1 answer:

serg [7]3 years ago

7 0

Answer:

Either 36.35 or 16.00173

Step-by-step explanation:

the reason im saying its either is due to not remembering whether do divide by inverse cosine to get on other side of equal sign or to just divide the cosine as is.

IF you are supposed to use inverse cosine:

16.00173

IF NOT:

36.35182

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Help please!

maks197457 [2]

The two inequalities are :

option B and option C

Explanation:

Daniel moves no more than 30 of his sheep and goats into another field. This means the summation of sheep and goats will be at maximum 30.

that is why it is $s+g\leq30$

And more than 7 of his animals are sheep means sheep are greater than 7. that is why = $s>7$

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4 years ago

a girl makes $15 per hour as a math tutor. Her paycheck is calculated by multiplying $15 times the number of hours she worked. H

White raven [17]

41 hours or more

to make $600 she will need to work 40 hours, but she wants to make more than $600 so she needs to work more than 40 hours.. 600/15=40

i hope this helps

5 0

4 years ago

SOMEONE PLEASE HELP WILL MARK BRAINLIST

tekilochka [14]

-5 +8

a) +(8-5)

b) Answer is 3

-6+(-12)

a) -6-12

b) Answer is -18

- I hope this helps!

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3 years ago

Of all customers purchasing automatic garage-door openers, 75% purchase Swedish model. Let X = the number among the next 15 purc

Lelechka [254]

Answer:

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = 0.2737

d) μ = 15*0.75 = 11.25. σ² = 11.25*0.25 = 2.8125

Step-by-step explanation:

X is a binomial random variable with parameters n = 15, p = 0.75. Therefore

$P(X=k) = {15 \choose k} * 0.75^{k}*0.25^{15-k}$

For any integer k between 0 and 15, and 0 for other values of k.

P(X>10) = P(X=11) + P(X=12)+ P(X=13)+P(X=14)+P(x=15)

$P(X=11) = {15 \choose 11} * 0.75^{11} * 0.25^4 = 0.2252$

$P(X=12) = {15 \choose 12} * 0.75^{12} * 0.25^3 = 0.2252$

$P(X=13) = {15 \choose 13} * 0.75^{13} * 0.25^2 = 0.1559$

$P(X=14) = {15 \choose 14} * 0.75^{14} * 0.25 = 0.0668$

$P(X=15) = {15 \choose 15} * 0.75^{15} = 0.0134$

Thus,

$P(X>10) = 0.2252+ 0.2252+ 0.1559+0.0668+0.0134 = 0.6865$

c) P(6 ≤ X ≤ 10) = P(X = 6) + P(X = 7) + P(X = 8) + P(X=9) + P(X=10)

$P(X=6) = {15 \choose 6} * 0.75^{6} * 0.25^9 = 0.0034$

$P(X=7) = {15 \choose 7} * 0.75^{7} * 0.25^8 = 0.0131$

$P(X=8) = {15 \choose 8} * 0.75^{8} * 0.25^7 = 0.0393$

$P(X=9) = {15 \choose 9} * 0.75^{9} * 0.25^6 = 0.0918$

$P(X=10) = {15 \choose 10} * 0.75^{10} * 0.25^{5} = 0.1652$

Thereofre,

$P(6 \leq X \leq 10) = 0.0034 + 0.0134 + 0.0393 + 0.0918 + 0.1652 = 0.2737$

d) μ = n*p = 15*0.75 = 11.25

σ² = np(1-p) = 11.25*0.25 = 2.8125

3 0

3 years ago

Tiva earns $48 of 6 hours of babysitting. Complete each statement if Tiva keeps earning her babysitting money at this rate. For

Charra [1.4K]

Answer:

Step-by-step explanation:

48=6

35=8.5

4 0

3 years ago