First question
42 students
Second question 65%
<h2>========================</h2>
<h2><em>yes </em><em>you </em><em>are </em><em>absolutely </em><em>correct</em><em>.</em><em>.</em><em>.</em><em>. </em></h2>
<em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em><em>⛔</em>
<h3><em>mark </em><em>it </em><em>as </em><em>brainliest</em><em>.</em><em>.</em><em>. </em><em>✌</em><em>✌</em><em>✌</em></h3>
There are two answers:
B) 5
C) 8
==============================================
Explanation:
If we had a triangle with sides a, b and c, then we can say
b-a < c < b+a
where b is larger than 'a'. This is the triangle inequality theorem
In this case, a = 5 and b = 9 so,
b-a < c < b+a
9-5 < c < 9+5
4 < c < 14
Telling us that c is some number between 4 and 14, not including either endpoint. If c is a whole number, then c could be any value from this set: {5,6,7,8,9,10,11,12,13}
We see that the numbers 5 and 8 are in this set. The values 3 and 15 are not in the set.
Answer:
zero(0)
Step-by-step explanation:
The additive identity of a set of number is a number such that the its sum with any of the numbers in the set would give a result that is equal to the number in that set.
In other words, say for example the set of numbers is rational, the additive identity of rational numbers is 0. This is because, given any rational number say <em>x</em>, adding zero to the number <em>x</em> gives the same number <em>x. </em>i.e
x + 0 = x
If x is say 2, then we have;
2 + 0 = 2
Since adding zero to rational numbers gives has no effect on the numbers, then zero (0) is the additive identity of rational numbers.
<em></em>