Can you resubmit your question so that I can give you a reasonable answer
6 + 2 < 9 + 3...u r correct
Given:
<span>11 11.5 10.5 17 14.5 14.5 18 17 19
Arrange in chronological order from least to greatest.
10.5 ; 11 ; 11.5 ; 14.5 ; 14.5 ; 17 ; 17 ; 18 ; 19
</span><span>I used an online lower and upper fence calculator to get the necessary data.
Minimum: 10.5
Maximum: 19
Q1: 11.25
Q2 or median: 14.5
Q3: 17.5
Interquartile range can be solved by subtracting the value of Q1 from the value of Q3
IQR = Q3 - Q1
IQR = 17.5 - 11.25
IQR = 6.25 CHOICE A. </span>
The general formula for geometric series is tn = a×rⁿ⁻¹. In this question, a (or a1) is 3, and r is 1.1, therefore the first ten terms would be 3×1.1⁰ (3) , 3×1.1¹ (3.3), 3×1.1² (3.63) and so on up until you get to 3×1.1⁹ or 7.07.
