Answer:
39.15
Step-by-step explanation:
Answer:
Population of fish in 2010 = 1,646 fish (Approx.)
Step-by-step explanation:
Given:
Population of fish in 2002 = 2100 fish
Decrease rate = 3% per year
Find:
Population of fish in 2010
Computation:
Number of year = 2010 - 2002
Number of year = 8 year
A = P[1+r]ⁿ
Population of fish in 2010 = Population of fish in 2002[1+(-3%)]ⁿ
Population of fish in 2010 = 2100[1-0.03]⁸
Population of fish in 2010 = 2100[0.97]⁸
Population of fish in 2010 = 2100[0.7837]
Population of fish in 2010 = 1645.77
Population of fish in 2010 = 1,646 fish (Approx.)
Answer:x=2y+6
Step-by-step explanation:
Really weird that y is the number of years but ok
Answer:
All of the following are examples of propositions: "The U. S. holds presidential elections every four years." "Bob bought a new car." "Suzanne has the measles."
