When
the ball is in the ground, its height is basically equal to zero thus making
our equation,
<span> -16t^2 + 272t + 1344 = 0</span>
Simplifying
the equation will give us,
<span> - t^2 + 17t + 84 = 0 or t^2 – 17t – 84 = 0</span>
Factoring
out the equation will give us,
<span> (t – 21)(t + 4) = 0</span>
Thus,
t = 21 or t = -4. -4 is an extraneous root. Thus, the answer is t = 21.
<span>Answer:
21 seconds</span>
255/56 = 4.55....
You can't have 0.55... buses so you round that up to 1.
Therefore 4+1 = 5 so 5 buses would be the minimum.
<h3>One possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively</h3><h3>Other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively</h3>
<em><u>Solution:</u></em>
<em><u>The volume of rectangular pyramid is given as:</u></em>

Given that,
<em><u>Rectangular pyramid has a volume of 190 cubic centimeters</u></em>
<em><u></u></em>
<em><u></u></em>
<em><u>Substitute, base area = 570 and height = 1</u></em>
Then we get,

Thus one possible set for the base area and height of the pyramid is 570 cm and 1 cm respectively
<em><u>Substitute, base area = 285 and height = 2</u></em>

Thus other possible set for the base area and height of the pyramid is 285 cm and 2 cm respectively
Answer: 5/2, 2.71, 2 3/4 , 5
Answer:
2(7y+4x+2z+1)
Step-by-step explanation:
Factor out the 2 from the expression