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Lina20 [59]
3 years ago
15

Manuel ate 1/3 of the crackers on a plate. His brother ate 1/4 of the crackers. There were 5 crackers left on the plate. How man

y crackers were on the plate, to begin with.
Mathematics
1 answer:
rewona [7]3 years ago
3 0

Answer:

12 crackers

Step-by-step explanation:

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What is the perimeter of a trapezoid having side-lengths 10 cm, 7 cm, 6 cm, and 7 cm? a. 15 cm c. 25 cm b. 20 cm d. 30 cm
prisoha [69]

Answer:

30

Step-by-step explanation:

6 0
3 years ago
What is the following is the solution to the equation 25^(z+2) = 125
maksim [4K]

First, rewrite the equation 25^{z+2} = 125 with the base equal to 5. Note that:

  • 25=5^2;
  • 125=5^3;
  • 25^{z+2}=(5^2)^{z+2}=5^{2\cdot (z+2)}.

Then

5^{2\cdot (z+2)}=5^3.

Since the bases are equal, you have that powers are equal too:

2\cdot (z+2)=3,\\ \\2z+4=3,\\ \\2z=3-4,\\ \\2z=-1,\\ \\z=-\dfrac{1}{2}.

Answer: z=-\dfrac{1}{2}.


3 0
4 years ago
-X-5y + z = 17
grin007 [14]

Answer:

x = -1 , y = -4 , z = -4

Step-by-step explanation:

Solve the following system:

{-x - 5 y + z = 17 | (equation 1)

-5 x - 5 y + 5 z = 5 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Swap equation 1 with equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

-x - 5 y + z = 17 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Subtract 1/5 × (equation 1) from equation 2:

{-(5 x) - 5 y + 5 z = 5 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 1 by 5:

{-x - y + z = 1 | (equation 1)

0 x - 4 y+0 z = 16 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Divide equation 2 by 4:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

2 x + 5 y - 3 z = -10 | (equation 3)

Add 2 × (equation 1) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x - y+0 z = 4 | (equation 2)

0 x+3 y - z = -8 | (equation 3)

Swap equation 2 with equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x - y+0 z = 4 | (equation 3)

Add 1/3 × (equation 2) to equation 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z/3 = 4/3 | (equation 3)

Multiply equation 3 by 3:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y - z = 4 | (equation 3)

Multiply equation 3 by -1:

{-x - y + z = 1 | (equation 1)

0 x+3 y - z = -8 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 3 to equation 2:

{-x - y + z = 1 | (equation 1)

0 x+3 y+0 z = -12 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Divide equation 2 by 3:

{-x - y + z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Add equation 2 to equation 1:

{-x + 0 y+z = -3 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Subtract equation 3 from equation 1:

{-x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Multiply equation 1 by -1:

{x+0 y+0 z = -1 | (equation 1)

0 x+y+0 z = -4 | (equation 2)

0 x+0 y+z = -4 | (equation 3)

Collect results:

Answer: {x = -1 , y = -4 , z = -4

8 0
3 years ago
In Death Valley, California, the highest ground temperature recorded was 94°C on July 15, 1972. In the formula C= 5/9 (F - 32) ,
gulaghasi [49]

Answer:

F=201.2\°

Step-by-step explanation:

we know that

\°C=\frac{5}{9}[\°F-32]

For C=94\°

substitute in the formula and solve for F

94=\frac{5}{9}[F-32]

(\frac{9}{5})*94=[F-32]

F=(\frac{9}{5})*94+32

F=201.2\°

8 0
3 years ago
What is greater 0 or 2x-6?​
katrin [286]

Answer

2x-6

i dont need a expansion

5 0
3 years ago
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