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3 years ago

Please expand (X+3)^4

Mathematics

2 answers:

Marta_Voda [28]3 years ago

4 0

(x+3)(x+3)(x+3)(x+3)

Sliva [168]3 years ago

4 0

That would be (x+3) (x+3) (x+3) (x+3)

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Suppose that the middle 68% of speeding ticket fines on a highway fall between 93.18 and 118. Give an approximate estimate of th

Anton [14]

Answer:

The approximate estimate of the standard deviation of the speeding ticket fines is of 12.41.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Middle 68% of speeding ticket fines on a highway fall between 93.18 and 118.

This means that 93.18 is one standard deviation below the mean and 118 is one standard deviation above the mean. That is, the difference between 118 and 93.18 is worth two standard deviations. So

$2s = 118 - 93.18$

$s = \frac{(118 - 93.18)}{2}$

$s = 12.41$

The approximate estimate of the standard deviation of the speeding ticket fines is of 12.41.

7 0

3 years ago

Find the reciprocal of the number. Multiply to check your answer.

iren [92.7K]

To find the reciprocal, you just flip the fraction upside down, so it would be D

4 0

3 years ago

Read 2 more answers

What is closer to zero 3/4, 1/3, -5/8, or -3/6?

aalyn [17]

Answer:

1/3

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Consider the function V=g(x), where g(x) =x(6-2x)(8-2x), with x being the length of a cutout in cm and V being the volume of an

Andrej [43]

Answer:

The maximum volume of the open box is 24.26 cm³

Step-by-step explanation:

The volume of the box is given as $V=g(x)$ , where $g(x)=x(6-2x)(8-2x)$ and $0\le x\le3$ .

Expand the function to obtain:

$g(x)=4x^3-28x^2+48x$

Differentiate wrt x to obtain:

$g'(x)=12x^2-56x+48$

To find the point where the maximum value occurs, we solve

$g'(x)=0$

$\implies 12x^2-56x+48=0$

$\implies x=1.13,x=3.54$

Discard x=3.54 because it is not within the given domain.

Apply the second derivative test to confirm the maximum critical point.

$g''(x)=24x-56$ , $g''(1.13)=24(1.13)-56=-28.88\:$

This means the maximum volume occurs at $x=1.13$ .

Substitute $x=1.13$ into $g(x)=x(6-2x)(8-2x)$ to get the maximum volume.

$g(1.13)=1.13(6-2\times1.13)(8-2\times1.13)=24.26$

The maximum volume of the open box is 24.26 cm³

See attachment for graph.

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4 years ago

A pair of jeans sells for $49.99. The sales tax rate is 6.5%. What is the total cost for the jeans including sales tax? Please

sergij07 [2.7K]

Answer: Total cost would be $53. 24 including tax which is $3.25

Step-by-step explanation:

6 0

3 years ago