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shutvik [7]
3 years ago
8

I have been struggling at this please help

Mathematics
1 answer:
Taya2010 [7]3 years ago
5 0

Answer:

21

Step-by-step explanation:

I shall change the pictures to letters

a + a + b = 40 --(1)

b - c = 7 --(2)

c + a = 19 --(3)

a - c + b = ?

From (1):

2a + b = 40

b = 40 - 2a --(4)

From (2):

b = 7 + c --(5)

Sub (4) into (5):

40 - 2a = 7 + c

c = 33 - 2a --(6)

Sub (6) into (3):

33 - 2a + a = 19

a = 14

Sub a = 14 into (4) and (6):

b = 40 - 2(14) = 12

c = 33 - 2(14) = 5

therefore, a - c + b = 14 - 5 + 12 = 21

Topic: simultaneous equations

If you would like to venture further into mathematics, you can check out my Instagram page (learntionary) where I post notes and mathematics tips. Thanks!

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Step-by-step explanation:

3 0
2 years ago
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Can anybody help meee
andre [41]

Answer:

a.) f(2) = 3

b.) if f(x) = 2

x=3

Step-by-step explanation:

Here you must notice that on the graph where x is 2, y or f(x) is at 3. This means that the answer where in the function of x, where the input 2, the output or y/f(x) is 3

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nikdorinn [45]
The GCF is the first answer
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3 years ago
If a bracelet takes 5/6 foot of string how much string will it take to make 12 bracelets
const2013 [10]
5/6 x 12


60 / 6  = 10

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3 0
3 years ago
A printer has a contract to print 100,000 posters for a political candidate. He can run the posters by using any number of plate
yulyashka [42]

Answer:

25

Step-by-step explanation:

From the given information;

Numbers of posters that can be printed in an hour = no of impression/hour × no of plate utilized in each impression.

= 1000x

Thus, the required number of hours it will take can be computed as:

\implies \dfrac{100000}{1000x} \\ \\ =\dfrac{100}{x}

cost per hour = 125

If each plate costs $20 to make, then the total number of plate will equal to 40x

∴

The total cost can be computed as:

C(x) = (\dfrac{100}{x}) \times 125 + 20 x --- (1)

C'(x) = (-\dfrac{12500}{x^2})  + 20  --- (2)

At C'(x) = 0

\dfrac{12500}{x^2} = 20

\dfrac{12500}{20} = x^2

x^2= 625

x = \sqrt{625}

x = 25

C'' (x) = -12500 \times \dfrac{-2}{x^3} +0

C'' (x) = \dfrac{25000}{x^3}

where; x = 25

C'' (x) = \dfrac{25000}{25^3}

C''(x) = 1.6

Thus, at x = 25, C'' > 0

As such, to minimize the cost, the printer needs to make 25 metal plates.

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