the price of a car was reduced to 25% off the car is now £14.625 work out what the car was before it was reduced

Here is an addition sentence. (13 + 5) + 5 = 23 Choose an equivalent addition sentence that shows the associative property of ad

ANTONII [103]

<span>(13 + 5) + 5 = 23
</span>
associative property of addition
<span>13 + (5 + 5) = 23</span>

6 0

4 years ago

Read 2 more answers

Suppose you surveyed a group of students to see how many CDs they owned. The results are displayed in the

Alex17521 [72]

You surveyed 30 students to see how many CDs they owned.

The number of students who owned 5 - 8 CDs was:

= 15

The number of students who owned 9 - 12 CDs was:

= 10

The number of students who owned 13 - 16 CDs was:

= 5

The number of students who owned 17 - 20 CDs was:

= 0

The total number of students surveyed is the sum of the above:

= 15 + 10 + 5 + 0

= 30 students

30 students were surveyed for this study.

<em>Find out more at brainly.com/question/16372388.</em>

7 0

3 years ago

Please help me I’m stuck

FrozenT [24]

Answer:

10.77 units

Step-by-step explanation:

By imaging an imaginery line at point before 1 units to be 4 units: b = 4 units

Therefore h = 11 - 1 = 10 units

Using Pythagoras theorem:

x² = h² + b² = 10² + 4² = 100 + 16 = 116

x = √116 = 10.77 units

8 0

3 years ago

A bag contains 4 blue marbles and 2 yellow marbles. Two marbles are randomly chosen (the first marble is NOT replaced before dra

VMariaS [17]

Answer:

0.4 = 40% probability that both marbles are blue.

0.0667 = 6.67% probability that both marbles are yellow.

53.33% probability of one blue and then one yellow

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

Step-by-step explanation:

To solve this question, we need to understand conditional probability(for the final question) and the hypergeometric distribution(for the first three, because the balls are chosen without being replaced).

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

What is the probability that both marbles are blue?

4 + 2 = 6 total marbles, which means that $N = 6$

4 blue, which means that $k = 4$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,4) = \frac{C_{4,2}*C_{2,0}}{C_{6,2}} = 0.4$

0.4 = 40% probability that both marbles are blue

What is the probability that both marbles are yellow?

4 + 2 = 6 total marbles, which means that $N = 6$

2 yellow, which means that $k = 2$

Sample of 2, which means that $n = 2$

This is P(X = 2). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 2) = h(2,6,2,2) = \frac{C_{2,2}*C_{4,0}}{C_{6,2}} = 0.0667$

0.0667 = 6.67% probability that both marbles are yellow.

What is the probability of one blue and then one yellow?

Total is 100%.

Can be:

Both blue(40%)

Both yellow(6.67%)

One blue and one yellow(x%). So

40 + 6.67 + x = 100

x = 100 - 46.67

x = 53.33

53.33% probability of one blue and then one yellow.

If you are told that both selected marbles are the same color, what is the probability that both are blue?

Conditional probability.

Event A: Both same color

Event B: Both blue

Probability of both being same color:

Both blue(40%)

Both yellow(6.67%)

This means that $P(A) = 0.4 + 0.0667 = 0.4667$

Probability of both being the same color and blue:

40% probability that both are blue, which means that $P(A \cap B) = 0.4$

Desired probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4}{0.4667} = 0.8571$

If you are told that both selected marbles are the same color, 0.8571 = 85.71% probability that both are blue

8 0

3 years ago

Evaluate the expression 5t + 2m for m = 7 and t = 2.

pantera1 [17]

Answer:

<h3>The answer is 24</h3>

Step-by-step explanation:

5t + 2m

m = 7 t = 2

Substitute the above values into the expression

That's

5(2) + 2(7)

10 + 14

24

Hope this helps you

5 0

4 years ago