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2 years ago

Ill mark brainliest I just don't understand

Mathematics

1 answer:

Misha Larkins [42]2 years ago

3 0

Answer:

a triangle always equals 180 degrees so

63+ 2x+8 + x+7 =180

solve for x

and then plug it back into original equation

let me know if this makes sense

glad to help you more if needed

Step-by-step explanation:

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James earn 5$ an hour babysitting. Determine whether the amount of money james earns babysitting is proportional to the number o

Marat540 [252]

Answer:

I believe 68%

Step-by-step explanation:

6 0

2 years ago

Please someone help me

FrozenT [24]

4. No
'And I think you can draw the diagram;)

7 0

3 years ago

Which equation could have been used to create this function table?

alina1380 [7]

A) y=3x
You can plug in the given values (inputs) of x to see if it creates the number in y (output).
3*1=3
3*2=6
3*3=9
3*4=12
3*5=15
3*6=18

All these values are true, therefore the equation y=3x is the correct answer.

:)

5 0

2 years ago

Jason accidentally locked himself out of his apartment, but remembered that he left a window open. The window is 8 feet above th

dalvyx [7]

Answer:

I Think Its 14 Feet.

Step-by-step explanation:

14 feet because the window is 8 feet high and he has to move it back 6 feet. So when you add 8 and 4 you would get the answer of 14 feet.

3 0

3 years ago

Read 2 more answers

Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi

Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

$P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}$

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

$P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483$

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0

3 years ago