Answer:
90 between 1000 and 9999
Step-by-step explanation:
The first digit cannot be 0. It can be nine other digits.
The second digit can be anything between 0 and 9.
To be palindromic the 2nd and 3rd digits must be the same.
And in addition, the 1st and 4 numbers must be the same.
So the answer is 9 * 10 = 90. That does seem too small, but try making a palindrome with the restrictions I have outlined. None of the examples you have given beginning with 8 are palindromic.
8118 is palindromic
8998 is also palindromic
9009 is palindromic
2002 is palindromic
There are only 90 of them.
Hello from MrBillDoesMath!
Answer:
x = 30
Discussion:
Note: I ignored the * in f*(x) as i don't know what it means. (If this is not what you intended, please indicate what * means)
f(x) = 2 sqrt(x-5) + 4
f(x) = 14
=>
14 = 2 sqrt(x-5) + 4 => subtract 4 from both sides
14 -4 = 2 sqrt(x-5) => divide both sides by 2
10/2 = sqrt(x-5) =>
5 = sqrt(x-5) => square both sides
5*5 = x-5 => add 5 to both sides
5*5 + 5 = x
25 + 5 = x
x = 30
Thank you,
MrB
Answer:
minimum maximum parabolas are equal then because of the circumference
Step-by-step explanation:
Yeah i could be your friend lol
Answer:
It's a photo of the problem. It's not a spam. Just so you could be sure. ;-)
Have a good day
