Ask question

Ask question

All categories

LuckyWell [14K]

2 years ago

6

At an ice cream shop, 4 of the last 10 cones sold had cookies and cream ice cream. Considering this data, how many of the next 1

5 cones sold would you expect to have cookies and cream ice cream?

2 answers:

telo118 [61]2 years ago

7 0

The answer is 6 cones

ale4655 [162]2 years ago

6 0

Answer:

6 cones

Step-by-step explanation:

4/10=2/5

2/5x3x3=6/15

6 cones

You might be interested in

Mrs. Juergen's class is building a model city from craft sticks. each house requires 267 sticks. the class will build 93 houses.

Radda [10]

All you need to do is 267 times 93 to get the exact answer. the questions says ABOUT how many sticks so we can round the numbers. we can turn 267 into 270 and 93 into 90 and then multiply 270 by 90 to get 24,300 popsicle sticks

6 0

2 years ago

What is the partial product of 2.3 x 2.6?

otez555 [7]

I’m pretty sure it’s 2.99

3 0

3 years ago

There are 3 red marbles, 4 yellow marbles, 8 pink marbles, and 3 green marbles in a bag. You randomly choose one. What is the pr

svp [43]

Answer:

16%

Step-by-step explanation:

add all of them together (total=18) and divide 3 by the total

You will get 0.16 and you turn it into a percentage by moving the decimal two places to the right

6 0

3 years ago

Read 2 more answers

A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop

Katyanochek1 [597]

Answer: $(0.367,\ 0.473)$

Step-by-step explanation:

The confidence interval for population mean is given by :-

$\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}$

, where $\hat{p}$ is the sample proportion, n is the sample size , $z_{\alpha/2}$ is the critical z-value.

Given : Significance level : $\alpha:1-0.99=0.01$

Sample size : n= 85

Critical value : $z_{\alpha/2}=2.576$

Sample proportion: $\hat{p}=\dfrac{36}{85}\approx0.42$

Now, the 99% confidence level will be :

$\hat{p}\pmz_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.42\pm(2.576)\sqrt{\dfrac{0.42(1-0.42)}{85}}\\\\\approx0.42\pm0.053\\\\=(0.42-0.053,\ 0.42+0.053)=(0.367,\ 0.473)$

Hence, the 99% confidence interval estimate of the true proportion of families who own at least one DVD player is $(0.367,\ 0.473)$

3 0

2 years ago

Factor (4x^3 - 20x^2) -(9x + 45)

stellarik [79]

Answer:

u cannot factor it not possible

Step-by-step explanation:

8 0

3 years ago