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3 years ago

HEL----PPPPpppppppppppppppppppppppppppppp

Mathematics

2 answers:

omeli [17]3 years ago

8 0

Answer:

Step-by-step explanation:

First order from smallest to largest.

70.8, 71.9, 72.1, 82.4, 85.3, 98.1.

Median is the middle number/s.

72.1+82.4/2 so The median is 77.25

Range is the largest number minus the smallest number.

85.3-70.8=14.5

Mode is the most repeated number.

Since there are no repeated numbers there is no mode.

Second question:

Again rearrage: 6, 9, 11, 14, 17

In order to make the median 10 you would have to add another 9 becasue

11+9/2 = 10

Third: remove 6 to make 12 the middle number

Fourth: add all numbers 90+x/6=20 so x has to be 30

Agata [3.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

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URGENT!!! 50 POINTS!!! URGENT!!!!!!! Consider the polynomial functions P (x) and Q (x) , where neither polynomial is a constant

Nutka1998 [239]

Answer:

Always

Sometimes

Never

Step-by-step explanation:

P(X) + Q(X)

Sum of two polynomials is always a polynomial.

For example, Let P(x) = 3x² and Q(x) = 5x

$$ \implies$ P(x) + Q(x) = 3x² + 5x

This is again a polynomial.

In other words, we can say that Polynomial is closed under addition.

P(x) . Q(x)

Product of two polynomials is again a polynomial.

Let P(x) = 2x and Q(x) = a constant function, 5

Then the product = 10x, is again a polynomial.

Multiplication of two polynomials is closed.

P(x) / Q(x)

This need not always be a polynomial. When Q(x) = a constant function zero, i.e., Q(x) = 0, then the function is not defined.

But let's say P(x) = 5x² and Q(x) = x.

$\frac{P(x)}{Q(x)}$ = $\frac{5x^2}{x}$ = 5x, a polynomial.

So, $\frac{P(x)}{Q(x)}$ is a polynomial sometimes.

We can, say Division is not always closed.

1/Q(x)

This could never be a polynomial. This is not even in the form of a polynomial. So, $\frac{1}{Q(x)}$ is never a polynomial.

Hence, the answer.

7 0

3 years ago

PLEASE SOMEONE HELP ME WITH THIS QUESTION I DONT GET IT ITS DUE TODAY

nadya68 [22]

-466820 sorry perdone

8 0

3 years ago

Triangle ABC has been rotated 90° to create triangle DEF. Write the equation, in slope-intercept form, of the side of triangle A

Ket [755]

the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1

<h3>How to determine the equation</h3>

From the figure given, we can deduce the coordinates of the sides

For A

A ( 4,2)

For B

B ( 4, 5)

C ( 1, 2)

D ( 2, -4 )

E ( 5, -4)

F ( 2, -1)

The slope for BC

Slope = $\frac{y2 - y1}{x2 - x1}$

Substitute the values for both B and C coordinates, we have

Slope = $\frac{2- 5}{1 - 4}$

Find the difference for both the numerator and denominator

Slope = $\frac{-3}{-3}$

Slope = 1

We have the rotation for both point ( 0, 1)

y - y1 = m ( x - x1)

The values for y1 and x1 are 1 and 0 respectively and the slope m is 1

Substitute the values

y - 1 = 1 ( x - 0)

y - 1 = x

Make 'y' the subject of formula

y = x + 1

Thus, the equation in the slope-intercept of the side of triangle ABC that is perpendicular to segment EF is y = x + 1

Learn more about linear graphs here:

brainly.com/question/4074386

#SPJ1

4 0

2 years ago

Plz help me with these two questions I have no idea how to do this

viktelen [127]

(7-3+4^3/2) / (9-5)
7-3+64/2) / 4
(7-3 + 32) / 4
(4 + 32) / 4
36/4 = 9

48 + 72
24(2 + 3)

8 0

4 years ago

A gardener already has four and one over 2 ft of fencing in his garage. He wants to fence in a square garden for his flowers. Th

NikAS [45]

<h2>Answer:</h2>

$6\frac{1}{2}$ <u>, "six and one over two ft".</u>

<h2>Step-by-step explanation:</h2>

Let's considerate the fact that the garden has a <u>square shape</u>.

<h3>1. Finding values of interest.</h3>

Amount of fence that the gardener already has: $4\frac{1}{2}$ ft.

Length of one side: $2\frac{3}{4}$ ft.

If one side measures $2\frac{3}{4}$ ft, and the square garden has 4 sides of equal length, because it's a square, then we must multiply the measure of one side by 4 to find the total length of fence needed:

$4*(2\frac{3}{4})=\\ \\4*(2+\frac{3}{4})=\\ \\(4*2)+(4*\frac{3}{4})=\\ \\8+(\frac{12}{4} )=\\ \\8+3=\\ \\11$

The gardener already has $4\frac{1}{2}$ , which equals $4 + \frac{1}{2}$ . Hence, the difference between the amount needed and the amount that the gardeneralready has will give us the remaining amount required. Let's do that:

$11-(4+\frac{1}{2} )=\\ \\11-(\frac{8}{2} +\frac{1}{2} )=\\ \\11-\frac{9}{2}= \\ \\\frac{22}{2} -\frac{9}{2}=\\\\ \frac{13}{2}$

<h3>3. Express your result.</h3>

$\frac{13}{2} =\\ \\\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{2}{2} +\frac{1}{2}= \\ \\6+\frac{1}{2}=\\ \\6\frac{1}{2}$

8 0

2 years ago